3 years ago

How many moles of oxygen can be formed from 250 grams of aluminum oxide

1 answer:

8 0

2Al₂O₃ = 4Al + 3O₂

M(A₂O₃)=101.96 g/mol
m(Al₂O₃)=250 g

n(O₂)=3m(Al₂O₃)/{2M(Al₂O₃)}

n(O₂)=3*250/{2*101.96}=3.678 mol

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<h3>Further explanation</h3>

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