SiCl4(L) + 2H2O(L) —>> SiO2(s) + 4HCl(aq)
We need balanced elements on both sides, products and reactants. We see from inspection we need to balance Cl, H, and O on both sides, reactants and products. So by adding 2moleH2O we need to add 4HCl to balance.
Answer: [Ne] 3s¹ sodium electron configuration
Answer:
A: 0.0028°C
Explanation:
Hopefully this helps!
0.514 L (liters)
