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Alexxandr [17]
3 years ago
7

What is the value of x in the equation -3x=4?

Mathematics
1 answer:
Softa [21]3 years ago
3 0

Answer:

- 1 1/3

Step-by-step explanation:

To solve this, simply divide 4 by -3. 4/-3 = -1 1/3, so that's your answer.

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Which polygon appears to be regular?
ivolga24 [154]

Answer:

  Figure A

Step-by-step explanation:

A regular polygon has all sides the same length and all angles the same measure. Only Figure A matches that description.

5 0
3 years ago
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QveST [7]
0.75 or 3/4 that’s your answer as a decimal and fraction :)
7 0
2 years ago
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How many 1-inch cubes do you need to create a cube with an edge length of 5 inches?
REY [17]
125, 1 - inch cubes.

5^{3}
Height = 5
Width = 5
Length = 5
3 0
3 years ago
Point M is located at (4, 6) on a coordinate grid. Point M is translated 8 units to the left and 9 units down to create point M.
weqwewe [10]

Answer:

D

Step-by-step explanation:

You can look at it like a right triangle being made with the vertical part being 9 and the horizontal part being 8, then you want to find the diagonal part. So that's the Pythagorean theorem


\sqrt{8^2+9^2}=12.042

8 0
3 years ago
In the past, 35% of the students at ABC University were in the Business College, 35% of the students were in the Liberal Arts Co
sukhopar [10]

Answer:

a. proportions have not changed significantly

Step-by-step explanation:

Given

Business College= 35 %

Arts College= 35 %

Education College = 30%

Calculated

Business College = 90/300= 9/30= 0.3 or 30%

Arts College= 120/300= 12/30= 2/5= 0.4 or 40%

Education College= 90/300= 9/30 = 0.3 or 30%

First we find the mean and variance of the three colleges using the formulas :

Mean = np

Standard Deviation= s= \sqrt{npq\\}

Business College

Mean = np =300*0.3= 90

Standard Deviation= s= \sqrt{npq\\}=\sqrt{0.3*0.7*300}= 7.94

Arts College

Mean = np =300*0.4= 120

Standard Deviation= s= \sqrt{npq\\}=\sqrt{0.4*0.6*300}=  8.49

Education College

Mean = np =300*0.3= 90

Standard Deviation= s= \sqrt{npq\\}=\sqrt{0.3*0.7*300}= 7.94

Now calculating the previous means with the same number of students

Business College

Mean = np =300*0.35= 105

Arts College

Mean = np =300*0.35= 105

Education College:

Mean = np =300*0.3= 90

Now formulate the null and alternative hypothesis

Business College

90≤ Mean≥105

Arts College

105 ≤ Mean≥ 120

Education College

U0 : mean= 90     U1: mean ≠ 90

From these we conclude that the  proportions have not changed significantly meaning that it falls outside the critical region.

8 0
3 years ago
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