Answer:
20 ( B )
Explanation:
Given data:
a and b are 10 map units apart
b and c are 20 map units apart
a and c = 30 map units apart
<em>condition </em>; Triple heterozygote testcrossed
number of progeny = 1000
<u>Determine the number of double crossover result </u>
P( crossover between a and b ) = 10/100 = 0.1
P( crossover between b and c ) = 20/100 = 0.2
p( double crossover ) = 0.1 * 0.2 = 0.02
hence number of double crossovers = number of progeny * 0.02
= 1000 * 0.02 = 20
Answer:
The physical infrastructure for X-ray crystallography structural biology includes synchrotrons, which are affordable by a nation. There are 47 in the world (lightsources.org). Each synchrotron provides a number of beamlines for experiments, usually including several optimized for macromolecular X-ray crystallography, often some for other structural biology techniques including SAXS (Small-Angle X-Ray Scattering) and CD (Circular Dichroism), and usually some beamlines for material sciences and other non-biological applications.
Explanation:
https://www.creative-biostructure.com/Data-Processing-and-Interpretation-584.htm
Explanation:
what language is this I don't understand it but hi
Three lots with parallel side boundaries extend from the avenue to the boulevard as shown in the diagram attached.
Given;
x + y + z = 140 metersAccording to the proportion theorem,

Solving for x, using cross multiplication:

Similarly,
x/40 = z/35
solving for z by cross multiplication,
z = 35x/40
z = 7x/8
Now, the third proportions,
y/30 = z/35
Solving for y,
y = 30z/35
y = 6z/7
x + y + z = 140
4y/3 + 6z/7 + 7x/8 = 140
(224y + 144z + 147x)/168 = 140
224y + 144z + 147x = 23520
Substitutoing z = 7x/8,
224y + (144 × 7x/8) + 147x = 23520
224y + 126x + 147x = 23520
224y + 273x = 23520
Now,
Substitute y = 3x/4
(224×3x/4) + 273x = 23520
168x + 273x = 23520
441x = 23520
x = 53.33
Now,
We know that
y = 3x/4
so,
y = 40
And,
z = 7x/8
Z = 46.66