The product of a <em>complex</em> number and its conjugate is (a + i b) · (a - i b), where a and b are <em>real</em> numbers, and the result for the <em>complex</em> number 2 + i 3 is 13.
<h3>What is the multiplication of a complex number and its conjugate</h3>
Let be a <em>complex</em> number a + i b, whose conjugate is a - i b. Where a and b are <em>real</em> numbers. The product of these two numbers is:
(a + i b) · (a - i b)
Then, we proceed to obtain the result by some algebraic handling:
a · (a + i b) + (- i b) · (a + i b)
a² + i a · b - i a · b - i² b²
a² - i² b²
a² + b²
If we know that a = 2 and b = 3, then the product of the complex number and its conjugate is:


To learn more on complex numbers: brainly.com/question/10251853
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7/12
12/7
1`2/7
7/12
a reciprocal you just flip the fraction
Answer:
A) 18.3
Step-by-step explanation:
Since adding b and a gives 19.
c must be less than 19.
So, A) 18.3 is the correct answer
-22 is your answer because all you have to do is take 4 away from -18 and you get -22
oops sorry wrong question. sorry if I confused anyone :(