A

Mathematics

1 answer:

kykrilka [37]2 years ago

8 0

Answer:

One possible answer would be they sold 80 student tickets and 30 adult tickets

Step-by-step explanation:

set up two inequalities, one to show number of tickets that can be sold, and the other is how much money they need to make

5x+10y G than or = 700

x+y L than or = 110

The first inequality shows that each student (x) ticket sells for $5, and each adult (y) ticket sells for $10, and the amound has to be greater or equal to 700.

The second inequality shows that both student and adult tickets sold have to be less than or equal to 110.

First find either x or y, in this case finding y was easier

y is g than or = to 30

This means that they sold at least 30 adult tickets= $300

With y, plug into the inequality x+y L than or = to 110 to find x

x is less than or = to 80

This means that they sold at most 80 student tickets = $400

Hope this helps!

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3 0

3 years ago

ratelena [41]

For the first interval (-1, 2), f(-1) = f(2), which means that the average rate of change on that interval is zero, so the correct option is A.

<h3>Over which interval the rate of change is zero?</h3>

For a function f(x) we define the average rate of change over the interval (a, b) is defined as:

R = (f(b) - f(a))/(b - a)

Here the function is:

f(x) = x^2 - x -1

And the rate of change will be zero on an interval (a, b) if and only if:

f(b) = f(a).

Notice that the first interval is (-1, 2)

f(-1) = (-1)^2 - (-1) - 1 = 1 + 1 - 1 = 1

f(2) = 2^2 - 2 - 1 = 4 - 2 - 1 =1

Then f(-1) = f(2), which means that the average rate of change on that interval is zero, so the correct option is A.

If you want to learn more about average rate of change: