If you take a look at my really poorly drawn diagram, we can see it is a trigonometry problem. The angle, however, is outside the triangle, and we can find the angle inside the triangle next to it by taking it away from 90°:
90°0' - 72°54' = 17°6' ≈ 17.1°.
We can find the other angles becuase one is 90° and the other is:
180°-90°-17°6'=72°54' ≈ 72.9°(which you can see if you know your angle theorems).
We now have diagram 2, nicely simplified so we can see where to go.
Using the Sine Rule, i.e.
![\frac{sin(A)}{a} = \frac{sin(B)}{b}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bsin%28A%29%7D%7Ba%7D%20%3D%20%5Cfrac%7Bsin%28B%29%7D%7Bb%7D%20)
We can rearrange to find our length b:
![b=a \frac{sinB}{sinA}](https://tex.z-dn.net/?f=b%3Da%20%5Cfrac%7BsinB%7D%7BsinA%7D%20)
Substituting numbers in:
![b=1191 \frac{sin(17.1)}{sin(72.9)} =366.399...ft](https://tex.z-dn.net/?f=b%3D1191%20%5Cfrac%7Bsin%2817.1%29%7D%7Bsin%2872.9%29%7D%20%3D366.399...ft)
b=366 feet.