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just olya [345]

3 years ago

7

The generator of a cone forms a 45 degree angle with the central axis. Let x be the degree measure of the angle formed by the pl

ane and the cones central axis. If a circle is formed, what is x?

1 answer:

svp [43]3 years ago

5 0

Answer:

90

Step-by-step explanation:

You might be interested in

Find the distance between the points given. (-3, 2) and (9, -3) A √37 B √61 C 13

Kitty [74]

Answer:

$\huge{ \fbox{ \sf{13 \: units}}}$

Option C is correct.

Step-by-step explanation:

$\star{ \sf{ \: Let \: the \: points \: be \: a \: and \: b}}$

$\star{ \sf{ \: let \: A(-3, 2) \: be \: (x1 \:, y1) \: and \: B(9, -3) \: be \: (x2 \:, y2) }}$

$\underline{ \sf{Finding \: the \: distance \: between \: the \: given \: points}} :$

$\boxed{ \sf{Distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}$

$\mapsto{ \sf{ \sqrt{ {(9 - ( - 3))}^{2} + {( - 3 - 2)}^{2} } }}$

$\mapsto{ \sf{ \sqrt{ {(9 + 3)}^{2} + {( - 3 - 2)}^{2} }}}$

$\mapsto{ \sf{ \sqrt{ {(12)}^{2} + {( - 5)}^{2} } }}$

$\mapsto{ \sf{ \sqrt{144 + 25}}}$

$\mapsto{ \sf{ \sqrt{169} }}$

$\mapsto{ \sf{ \sqrt{ {(13)}^{2} } }}$

$\mapsto{ \sf{ 13 \: units}}$

Hope I helped!

Best regards! :D

~ $\text{TheAnimeGirl}$

7 0

3 years ago

HELP PLEASE THANK YOU

pochemuha

Answer:

hiiiiiiiiiiii I like uiuuuuuus

8 0

3 years ago

Determine if the following side lengths could form a triangle.

kykrilka [37]

Answer: Determine if the following side lengths could form a triangle.

Prove your answer with an inequality.

8,17,24

Step-by-step explanation:

Determine if the following side lengths could form a triangle.

Prove your answer with an inequality.

8,17,24

4 0

3 years ago

Quadratics need help making parabola

timama [110]

Answer:

The equation of the parabola is $y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4$ , whose real vertex is $(x,y) = (2, -5.333)$ , not $(x,y) = (2, -5)$ .

Step-by-step explanation:

A parabola is a second order polynomial. By Fundamental Theorem of Algebra we know that a second order polynomial can be formed when three distinct points are known. From statement we have the following information:

$(x_{1}, y_{1}) = (-2, 0)$ , $(x_{2}, y_{2}) = (6, 0)$ , $(x_{3}, y_{3}) = (0, -4)$

From definition of second order polynomial and the three points described above, we have the following system of linear equations:

$4\cdot a -2\cdot b + c = 0$ (1)

$36\cdot a + 6\cdot b + c = 0$ (2)

$c = -4$ (3)

The solution of this system is: $a = \frac{1}{3}$ , $b = - \frac{4}{3}$ , $c = -4$ . Hence, the equation of the parabola is $y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4$ . Lastly, we must check if $(x,y) = (2, -5)$ belongs to the function. If we know that $x = 2$ , then the value of $y$ is:

$y = \frac{1}{3}\cdot (2)^{2}-\frac{4}{3}\cdot (2) - 4$

$y = -5.333$

$(x,y) = (2, -5)$ does not belong to the function, the real point is $(x,y) = (2, -5.333)$ .

5 0

3 years ago

PLZ ans have mocks plz

Yanka [14]

Answer:

The table will be:

x |-2 | -1 | 0 | 1 | 2

y | 1 | 4 | 5 | 4 | 2

Step-by-step explanation:

The function is:

$y=5-x^{2}$

a) The x values of the table is:

x |-2 | -1 | 0 | 1 | 2

So, when x = -2, y will be:

$y(-2)=5-(-2)^{2}=5-4=1$

Doing the same with the other x values we have:

$y(-1)=5-(-1)^{2}=5-1=4$

$y(0)=5-(0)^{2}=5$

$y(1)=5-(1)^{2}=5-1=4$

$y(2)=5-(2)^{2}=5-4=1$

The table will be:

x |-2 | -1 | 0 | 1 | 2

y | 1 | 4 | 5 | 4 | 1

I hope it helps you!

5 0

3 years ago