Answer:
c. 441ft^2
Step-by-step explanation:
Area is height times length and since it's a square, safe to say that the sides are equal in length. So square root both of the given areas of the 2 square:
= 29
= 20
Now u have side b and c of the triangle, it's a right triangle so use the Pythagorean theorem a^2 + b^2 = c^2
a^2 + b^2 = c^2
a^2 + 20^2 = 29^2
a^2 + 400 = 841
subtract 4 from both sides
a^2 = 441
square root both sides
a = 21
Now the side a of the triangle is also a side of the small square therefore
21^2 = 441
Answer:
3,432 m²
Step-by-step explanation:
The amount of aluminum in square meters needed to make the mailboxes = 1863(surface area of each mailbox)
Surface area of each mail box = ½(surface area of cylinder) + (Surface area of rectangular prism/box - area of the surface of the box that joins the half-cylinder)
✔️Surface area of ½-cylinder = ½[2πr(h + r)]
r = ½(0.4) = 0.2 m
h = 0.6 m
π = 3.14
Surface area of ½-cylinder = ½[2*3.14*0.2(0.6 + 0.2]
= 0.628(0.8)
Surface area of ½-cylinder = 0.5024 m²
✔️Surface area of the rectangular box/prism = 2(LW + LH + WH)
L = 0.6 m
W = 0.4 m
H = 0.55 m
Surface area = 2(0.6*0.4 + 0.6*0.55 + 0.4*0.55)
Surface area of rectangular box = 1.58 m²
✔️Area of the surface joining the half cylinder and the box = L*W = 0.6*0.4 = 0.24 m²
✅Surface area of 1 mailbox = (0.5024) + (1.58 - 0.24)
= 0.5024 + 1.34
= 1.8424
Amount of aluminum needed to make 1863 mailboxes = 1863 × 1.8424 = 3,432.3912
= 3,432 m²
X/5 = 24/8
(because the triangles are similar)
x/5 = 3
x = 5*3 = 15 Answer
a/27 = 8/24 = 1/3
a = 9 Answer
Answer:
Step-by-step explanation:
c
