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3 years ago

Whats the standard form of 4 million 2 hundred sixteen thousand ninety

Mathematics

2 answers:

tiny-mole [99]3 years ago

7 0

Standard form:
4,216,090

love history [14]3 years ago

5 0

The answer to your question is 4,216,090

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Express the vector ModifyingAbove Upper P 1 Upper P 2 with right arrowP1P2 in the form Bold v equals v 1 Bold i plus v 2 Bold j

Tatiana [17]

Answer:

$\overrightarrow{P_1P_2}=-5\textbf{i}-4\textbf{j}-6\textbf{k}$

Step-by-step explanation:

$\overrightarrow{P_1P_2}=(P_2-P_1)\cdot(\textbf{i},\textbf{j},\textbf{k})=(-5-0)\textbf{i}+(-3-1)\textbf{j}+(-9-(-3))\textbf{k}\\\\\overrightarrow{P_1P_2}=-5\textbf{i}-4\textbf{j}-6\textbf{k}$

3 0

3 years ago

URGENT PLEASE HELP x/240 = 82/100 what is X?

Zielflug [23.3K]

x/240 = 82/100

240 : 100 = 2.4

so 240 is divided with 2,4 giving 100, this will work with 82 too. So, 82 × 2.4 = 196,8

Answer : x = 196,8

prove :

196,8/240 = 82/100 = 41/50

see the picture

7 0

3 years ago

Read 2 more answers

I don't know how to do this

Gre4nikov [31]

Answer:

x = -11/5 and y = 24/5

Step-by-step explanation:

Use elimination.

First, we need to multiply so that at least one variable can cancel out.

We can multiply the top equation by 2.

So we get

4x + 6y = 20

Then, we can use elimination.

The x's cancel out.

So we get 5y = 24

Or y = 24/5

Then, we can plug in this y value back into the first equation to find x.

2x + 3(24/5) = 10

2x + 72/5 = 50/5

2x = -22/5

x = -11/5

So x = -11/5 and y = 24/5

5 0

3 years ago

I cant figure nothing this out help me pleaseee

Arturiano [62]

Answer:

Well in set A, all of the sides are the same length but they are different shapes.

In set B, all of the angles are the same, they are just differnet shapes.

Hope this helps! :)

4 0

3 years ago

If the local linear approximation of f(x) = 2cos x + e^2x at x = 2 is used to find the approximation for f(2.1), then the % erro

yKpoI14uk [10]

Answer-

The % error of this approximation is 1.64%

Solution-

Here,

$\Rightarrow f(x) = 2\cos x + e^{2x}$

$\Rightarrow f'(x) = -2\sin x + 2e^{2x}$

And,

$\Rightarrow f(2) = 2\cos 2 + e^{4}$

$\Rightarrow f'(2) = -2\sin 2 + 2e^{4}$

Taking (2, f(2)) as a point and slope as, f'(2), the function would be,

$\Rightarrow y-y_1=m(x-x_1)$

$\Rightarrow y-(2\cos 2 + e^{4})=(-2\sin 2 + 2e^{4})(x-2)$

$\Rightarrow y=(-2\sin 2 + 2e^{4})(x-2)+(2\cos 2 + e^{4})$

The value of f(2.1) will be

$\Rightarrow y=(-2\sin 2 + 2e^{4})(2.1-2)+(2\cos 2 + e^{4})$

$\Rightarrow y=(-2\sin 2 + 2e^{4})(0.1)+(2\cos 2 + e^{4})$

$\Rightarrow y=64.5946$

According to given function, f(2.1) will be,

$\Rightarrow f(2.1) = 2\cos 2.1 + e^{2(2.1)}$

$\Rightarrow f(2.1) = 65.6766$

$\therefore \%\ error=\dfrac{65.6766-64.5946}{65.6766}=0.0164=1.64\%$

5 0

3 years ago