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3 years ago

Use the number line to add the fractions. help plz look at picture

Mathematics

1 answer:

mr_godi [17]3 years ago

5 0

Answer:

$\frac{1}{6}$

Step-by-step explanation:

$- \frac{1}{2} + \frac{2}{3} = - \frac{3}{6} + \frac{4}{6} \\\\ - \frac{3}{6} + \frac{4}{6} = \frac{1}{6}$

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Evaluate P(5, 2) 20 60 240 10

vesna_86 [32]

P(5,2) = n! /(n-r)!

n = 5, r = 2:

= (5 x 4 x 3 x 2 x 1 ) / 3 x 2 x 1

Cancel out common factors:

= 5 x 4 = 20

The answer is 20.

3 0

3 years ago

Read 2 more answers

Find the value of x. log 3 x = 4 A.) 7 B.) 12 C.) 27 D.) 81

lakkis [162]

Hello from MrBillDoesMath!

Answer:

Choice D, 81

Discussion:

By log 3x = 4 I presume that "3" is the base not a multiplier of x. Assuming it is the base, then the equation is equivalent to

x = 3^4

= 81

This is Choice D.

Thank you,

MrB

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3 years ago

A rectangular sandbox has an area of 55 square feet. find the length and width of the box if the length is one more than twice t

Dmitrij [34]

Answer:

The length is 5

The width is 11

Step-by-step explanation:

11 is more than two times bigger than 5

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3 years ago

Find the solutions to the equation below. Check all that apply. x2 - 4 = 0

Gennadij [26K]

Answer:

Step-by-step explanation:

First you add 4 to both sides and get

2x=4

then you divide by 2 and get

4/2=x

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3 years ago

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Chemistry is an experimental science in which a consistent system of measurements is used. Scientists throughout the world use t

Elena L [17]

Answer:

(a) 142 km trip requires 15.16 Liters of Gasoline

(b) The money spent is 69.34 euros or $87.37.

(d) 4 lb of candy contains 0.559 kg of dietary fat.

Step-by-step explanation:

(a)

Given that;

Mileage = 22 mi/gal

Converting it to km/L

Mileage = (22 mi/gal)(1 gal/3.78 L)(1 km/0.6214 mi)

Mileage = 9.36 km/L

Now, the gasoline required for 142 km trip:

Gasoline Required = (Length of trip)/(Mileage)

Gasoline Required = (142 km)/(9.36 km/L)

Gasoline Required = 15.16 L

(b)

Given that;

Mileage = 30 mi/gal

Converting it to km/L

Mileage = (30 mi/gal)(1 gal/3.78 L)(1 km/0.6214 mi)

Mileage = 12.77 km/L

Now, the gasoline required for 142 km trip:

Gasoline Required = (Length of trip)/(Mileage)

Gasoline Required = (115 km/day)(7 days/week)/(12.77 km/L)

Gasoline Required = 63 L/week

Now, we find the cost:

Weekly Cost = (Gasoline Required)(Unit Cost)

Weekly Cost = (63 L/week)(1.1 euros/L)

Weekly Cost = 69.34 euros/week = $87.37

since, 1 euro = $1.26

(c)

Average Speed = (Distance Travelled)/(Time Taken)

Average Speed = 200 m/20.9 s

Average Speed = (9.57 m/s)(3600 s/1 h)(1 km/ 1000 m)

Average Speed = 34.45 km/h

(d)

22.7 g piece contains = 7 g dietary fat

(22.7 g)(1 lb/453.592 g) piece contains = (7 g)(1 kg/1000 g) dietary fat

0.05 lb piece contains = 0.007 kg dietary fat

1 lb piece contains = (0.007/0.05) kg dietary fat

4 lb piece contains = 4(0.007/0.05) kg dietary fat

4 lb piece contains = 0.559 kg dietary fat

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4 years ago