The problem is simply asking as to convert the measurement from the smaller scale to the actual scale. For this, we simply multiply the factor to the smaller measurement. We do as follows:

Length = 1 1/8 x 8 = 9 ft

Hope this helps.

4 0

4 years ago

Read 2 more answers

(d) Sandy’s gross annual income is $51,350. She is paid biweekly and has 5% deducted from her paycheck for her 403(b). Her emplo

worty [1.4K]

Based on the annual income, the payment period, and the amount deducted for the 403(b), the amount deposited into Sandy's 403(b) is $220.

<h3>How much is deposited into Sandy's 403(b)?</h3>

First find the biweekly income:

= 51,350 / (52 weeks / 2 )

= 51,350 / 21 weeks

= $2,445.24

5% is deducted from her wages and the employer matches 4% of the salary. The amount deposited is:

= (5% + 4%) x 2,445.24

= $220

Find out more on 403(b) at brainly.com/question/2908111.

8 0

2 years ago

The table shows the rate at which water is being pumped into a swimming pool. Time (min) 2 4 8 12 Amount (gal) 44 88 176 264 5 U

trapecia [35]

The unit rate is 22 gal/min. So, you have

$\begin{gathered} \frac{22\text{ gal}}{1\text{ min}}=\frac{x\text{ gal}}{1\frac{1}{2}\text{ min}} \\ \text{ Multiply }by\text{ }1\frac{1}{2}\text{ min on both sides of the equation} \\ \frac{22\text{ gal}}{1\text{ min}}\cdot1\frac{1}{2}\text{ min}=\frac{x\text{ gal}}{1\frac{1}{2}\text{ min}}\cdot1\frac{1}{2}\text{ min} \\ 22\cdot\frac{3}{2}\text{ gal }=x\text{ } \end{gathered}$ $\begin{gathered} \text{Because } \\ 1\frac{1}{2}=\frac{1\cdot2+1}{2}=\frac{2+1}{2}=\frac{3}{2} \end{gathered}$

Then, you have

$\begin{gathered} 22\cdot\frac{3}{2}\text{ gal }=x\text{ gal} \\ \frac{66}{2}\text{ gal }=x \\ 33\text{ gal = x} \end{gathered}$

So, a minute and a half after 12 minutes, an additional 33 gallons will be pumped in. A total of 297 gallons

$264\text{ gal + 33 gal = }297\text{ gal}$

will have been pumped into the pool after 13 and a half minutes.

4 0

1 year ago