3 years ago

4/10

1 answer:

8 0

-4 yards

Some people find this helpful to picture or draw on a number line. Start at zero, go left to -5. Go 2 more spaces/marks left to -7, then go right three spaces to -4.

You might be interested in

Rational exponents: product rule simplify v^3/4 multiply v^5/7

marusya05 [52]

Answer:

$v\sqrt[28]{v^{13}}$

Step-by-step explanation:

The exponent rules that apply are ...

$(a^b)(a^c)=a^{b+c}\\\\a^{\frac{b}{c}}=\sqrt[c]{a^b}$

Using these rules for your product, we have ...

$v^{\frac{3}{4}}\times v^{\frac{5}{7}}=v^{\frac{3}{4}+\frac{5}{7}}\\\\=v^{\frac{41}{28}}=v\cdot v^{\frac{13}{28}}=v\sqrt[28]{v^{13}}$

6 0

3 years ago

Given the figure below, find the values of x and z. 29 (8x + 37) • (10x - 1)

pantera1 [17]

Answer:

idk

Step-by-step explanation:

7 0

3 years ago

Find the slope of the line that passes through points (2, 8) and (1, 3)

Paha777 [63]

Answer:

Your slope would be 5

Step-by-step explanation:

Since we know 2 points we'd use the formula

$M=\frac{y_{2}-y_{1} }{x_{2}-x_{1}}$

$X_{1} = 2$

$X_{2}=1$

$y_{1}=8$

$Y_{2}=3$

So your equation would be

$M=\frac{3-8}{1-2}$

Than you would subtract each of them leaving you with this:

$M=\frac{-5}{-1}$

When you divide the two negative numbers that would leave you with your slope, which is 5.

-5 ÷ -1 = 5

I hope this help.

5 0

3 years ago

Can some one please help me

Alja [10]

$-\sqrt{29}-irrational\\\\-\sqrt{25}=-5-rational\\\\44.\overline{91}=44.\frac{91}{99}-rational\\\\-\frac{6}{19}-rational\\\\-6\pi-irrational$

6 0

3 years ago

Read 2 more answers

If f(x)=x/2-2 and g(x)=2x^2+x-3, find (f+g)(x)

Lelu [443]

Hello :
If f(x)=x/2-2 and g(x)=2x^2+x-3, find (f+g)(x)
(f+g)(x)= f(x) +g(x) = x/2-2 +2x²+x-3 = x/2 +2x²+x-5
(f+g)(x)= (x+4x²-2x-10) /2
(f+g)(x)= (4x²+3x-10)/2 = 2x²+3/2 x -5

4 0

4 years ago

Read 2 more answers