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gtnhenbr [62]
3 years ago
5

Please help AGAIN PLEASE?

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
5 0

Answer:

C. T

Step-by-step explanation:

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The first two terms in an arithmetic progression are -2 and 5. The last term in the progression is the only number in the progre
Rudik [331]

Given:

The first two terms in an arithmetic progression are -2 and 5.

The last term in the progression is the only number in the progression that is greater than 200.

To find:

The sum of all the terms in the progression.

Solution:

We have,

First term : a=-2

Common difference : d = 5 - (-2)

                                      = 5 + 2

                                      = 7

nth term of an A.P. is

a_n=a+(n-1)d

where, a is first term and d is common difference.

a_n=-2+(n-1)(7)

According to the equation, a_n>200.

-2+(n-1)(7)>200

(n-1)(7)>200+2

(n-1)(7)>202

Divide both sides by 7.

(n-1)>28.857

Add 1 on both sides.

n>29.857

So, least possible integer value is 30. It means, A.P. has 30 term.

Sum of n terms of an A.P. is

S_n=\dfrac{n}{2}[2a+(n-1)d]

Substituting n=30, a=-2 and d=7, we get

S_{30}=\dfrac{30}{2}[2(-2)+(30-1)7]

S_{30}=15[-4+(29)7]

S_{30}=15[-4+203]

S_{30}=15(199)

S_{30}=2985

Therefore, the sum of all the terms in the progression is 2985.

6 0
3 years ago
Find the value of a square + b square when a+b = 8 and ab = 10
Ne4ueva [31]

As we know,

\boxed{ \boxed{(a + b) {}^{2}  =  {a}^{2}  +  {b}^{2}  + 2ab}}

now, let's plug the given values to find a² + b²

  • (8) {}^{2}  =  {a}^{2}  +  {b}^{2}  + (2 \times 10)

  • 64 =   {a}^{2}  +  {b}^{2}  + 20

  • {a}^{2} +   {b}^{2}  = 64 - 20

  • a {}^{2} +  b {}^{2}  = 44
5 0
3 years ago
I'd Point A is located at (9,2) on a coordinate plane and point B is located at (-9,10), what is the distance between the two po
Fiesta28 [93]
Draw the triangle and then use Pythagoras' theorem

distance = \sqrt{18 ^{2} +8 ^{2}   }
              = 19.70 (2dp) 
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3 years ago
Need help pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee<br><br><br>What is (f⋅g)(x)?
Sergio039 [100]

just need to multiply and axpand ?

( {x}^{2}  + 2)( {x}^{3}  - 4x + 2) =  {x}^{2} ({x}^{3}  - 4x + 2) + 2({x}^{3}  - 4x + 2) \\  =  {x}^{5}  - 4 {x}^{3}  + 2 {x}^{2}  + 2 {x}^{3}  - 8x + 4 \\  =  {x}^{5}  - 2 {x}^{3}  + 2 {x}^{2}  - 8x + 4

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3 years ago
Fing the value of x, -3(2x-9)=3(16-x)
Ksivusya [100]

Answer:

x= -7

Step-by-step explanation:

4 0
3 years ago
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