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kotegsom [21]
3 years ago
8

How do electromagnetic forces work?

Physics
1 answer:
zlopas [31]3 years ago
4 0
It attracts two charged particles which are separated by a definitive distance.......
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Define a dipole. Hence, write the expression for calculating the electric moment of a dipole​
Aleksandr-060686 [28]

Answer:

Explanation:

An electric dipole is formed by two point charges +q and −q connected by a vector a. The electric dipole moment is defined as p = qa

4 0
1 year ago
a concrete cube of side 0.50 m and uniform density 2.0 x 103 kg m–3 is lifted 3.0 m vertically by a crane. what is the change in
AlladinOne [14]

Answer:

Change in potential energy = 7350 Joules

Explanation:

It is given that,

Side of cube, a = 0.5 m

Density of cube, d=2\times 10^3\ kg/m^3

The cube is lifted vertically by a crane to a height of 3 m

We know that, density d=\dfrac{m}{V}

So, m = d × V  (V = volume of cube = a³)

m=2\times 10^3\ kg/m^3\times (0.5\ m)^3

m = 250 kg

We have to find the change in potential energy of the cube. At ground level, the potential energy is equal to 0.

Potential energy at height h is given by :

PE=mgh

PE = 250 kg × 9.8 m/s² ×3 m

PE = 7350 Joules

So, change in potential energy of the cube is 7350 Joules.

5 0
3 years ago
Read 2 more answers
Describe a vibration that is not periodic. NO LINKS PLEASE
Paraphin [41]

Answer:

1)The position change of almost any manually operated room light switch.

2) Sunlight striking a point on the ground on a partly cloudy and windy day

Explanation:

4 0
2 years ago
Why is it not suitable to determine the volume of an irregular charcoal using displacement method ​
AleksandrR [38]

Answer:

Displacement method of volume measurement is no suitable

Explanation:

Displacement method of volume measurement is no suitable for the objects that do not get immersed into the water completely because of the hindrance in accuracy of the measurement.

4 0
3 years ago
BEST ANSWER GETS BRAINLIEST!
wel

Answer:

Distance = 16.9 m

Explanation:

We are given;

Power; P = 70 W

Intensity; I = 0.0195 W/m²

Now, for a spherical sound wave, the intensity in the radial direction is expressed as a function of distance r from the center of the sphere and is given by the expression;

I = Power/Unit area = P/(4πr²)

where;

P is the sound power

r is the distance.

Thus;

Making r the subject, we have;

r² = P/4πI

r = √(P/4πI)

r = √(70/(4π*0.0195))

r = √285.6627

r = 16.9 m

8 0
3 years ago
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