Please help me with the unit assessment i have no idea any of the answers
        
             
        
        
        
Explanation:
It is given that,
Speed of the ball, v = 10 m/s
Initial position of ball above ground, h = 20 m
(a) Let H is the maximum height reached by the ball. It can be calculated using the conservation of energy as :
 
             


h' = 5.1 m
The maximum height above ground, 
H = 5.1 + 20 
H = 25.1 meters
So, the maximum height reached by the ball is 25.1 meters.
(b) The ball's speed as it passes the window on its way down is same as the initial speed i.e. 10 m/s. 
Hence, this is the required solution.                               
 
        
             
        
        
        
Answer:
0.235 nC
Explanation:
Given:
 = the magnitude of electric field = = the magnitude of electric field = 
 = the magnitude of electric force on each antenna = = the magnitude of electric force on each antenna = 
 = The magnitude of charge on each antenna = The magnitude of charge on each antenna
Since the electric field is the electric force applied on a charged body of unit charge. 

Hence, the value of q is 0.235 nC.
 
        
             
        
        
        
Answer:  When we use an analogy that represents the expanding universe with the surface of an expanding balloon, what does the inside of the balloon represent? The inside of the balloon does not represent any part of our universe.
 
        
             
        
        
        
A motion where gravity is the only force acting upon it