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3 years ago

Boojho made light from a laser torch to fall on a prism. Will he be able to observe a band

Physics

1 answer:

fgiga [73]3 years ago

7 0

Answer:

It depends on whether it is a white light that hits the prison.

Explanation:

If the light from the laser is not white then he wont be able to see all seven colours because it is only a white light that absorbs other colours and when it hits the prism it will refract and therefore he will see all seven colours

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Find the weight of a 2000 kg elaphant

Vika [28.1K]

19,600 Newtons (about 4,400 pounds).

On Earth only.

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3 years ago

What uniform magnetic field, applied perpendicular to a beam

schepotkina [342]

Answer:

The magnetic field is $2.11\times10^{-5}\ T$

Explanation:

Given that,

Speed $v=1.30\times10^{6}\ m/s$

Radius = 0.350 m

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Using formula of magnetic field

$B =\dfrac{mv}{qr}$

Where, m = mass of electron

v = speed of electron

q = charge of electron

r = radius

Put the value into the formula

$B=\dfrac{9.1\times10^{-31}\times1.30\times10^{6}}{1.6\times10^{-19}\times0.350}$

$B=2.11\times10^{-5}\ T$

Hence, The magnetic field is $2.11\times10^{-5}\ T$

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4 years ago

750 million years ago, there was enough Uranium-235 present in Oklo, Gabon to have a natural fission reactor occur and generate

Komok [63]

<span>With a half-life of 700 million years, U-235 would have had twice as much mass at a time 700 MYA. This would have put the mass at 100kg at that time. Going back another 50 million years would be (50/700) or 1/14 of the half-life, or (1/2 * 1/14), or 1/28 of the total mass. 1/28 of 100kg is 3.57kg, so the amount present at the 750MYA mark would be approximately 103.57kg of U-235.</span>

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4 years ago

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D, a<span>s a sound source moves away from a stationary object, the sound waves. It is the opposite of what happens. </span>

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3 years ago

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il63 [147K]

Answer:

v= 8.8*10⁷ m/s

Explanation:

Assuming no friction present, the change in electrical potential energy, must be equal in magnitude, to the change in kinetic energy of the electron.
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$\Delta U = (-e)*\Delta V$