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valentinak56 [21]
3 years ago
12

Find two numbers if their sum is -11 and their difference is 41

Mathematics
2 answers:
larisa [96]3 years ago
8 0

Answer:

The numbers are 12 and −29

Step-by-step explanation:

ale4655 [162]3 years ago
6 0

Answer:

x = 15

y = -26

hence, the numbers are 15 and -26

Step-by-step explanation:

let's take the numbers be x and y

now, we know

=》x + y = -11

=》x - y = 41

so, if we add these equations we get,

=》x + y + x - y = -11 + 41

=》2x = 30

=》x = 30 ÷ 2

=》x = 15

replacing the value of x in the equation 1, we get :

=》x + y = -11

=》15 + y = -11

=》y = -11 - 15

=》y = -26

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tresset_1 [31]

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Step-by-step explanation:

Ok so cos(x) = -4/5 and we know that:

sin^2(x) + cos^2(x) = 1.

If we plug that in and solve for sin(x) we get:

sin^2(x) = \frac{9}{25} \\sin(x) = \frac{3}{5}

Now we have to consider: <em>is sin(x) positive or negative?</em>

We have that \pi  < x < \frac{3\pi }{2}.

From the unit circle, we know that sin(x) is negative in this range. Therefore sin(x) actually equals -3/5.

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Here's where another important equation comes in:

sin(\alpha  + \beta ) = sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta)

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sin(x + pi/2) = -4/5

7 0
3 years ago
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