<span>f(x)= 50x
</span><span>y = k x
k is variation
so k= 50
D is the right option
hope it helps
</span>
Answer:
7.28 miles
Step-by-step explanation:
Suppose the distance at closest approach is represented by x. Then the distance to the point of closest approach at the first sighting is ...
d1 = x·tan(62°)
At the second sighting, the distance to the point of closest approach is ...
d2 = x·tan(38°)
The difference of these distances is 8 miles, so we have ...
d1 -d2 = 8 = x(tan(62°) -tan(38°))
Dividing by the coefficient of x, we find ...
x = 8/(tan(62°) -tan(38°)) ≈ 7.2764 . . . . miles
The point of closest approach is about 7.28 miles from the landmark.
1. The linear equation:
y = m x + b
m = 3
- 2 = 3 · 1 + b
- 2 = 3 + b
b = - 5
Answer: A ) y = 3 x - 5
2. We will solve the system of equations:
12 = - 4 m + b / · ( - 1 )
23 = 7 m + b
----------------------
- 12 = 4 m - b
+
23 = 7 m + b
--------------------
11 = 11 m, m = 1, b = 16
Answer: A ) y = x + 16
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