The answer is 945. i hope this helps
Table 1
Input (x) 1 3 5 5 9
Output (y) 7 16 19 20 28
We know that a function is a relation where each input or x-value of the X set has a unique y-value or output of the Y set.
In other words, we can not have duplicated inputs as there should be only 1 output for each input.
From Table 1, it is clear that:
- Each input or x-value of the X set has a unique y-value or output of the Y set.
- There is no duplicated input (repeated x value).
Therefore, Table 1 represents a function.
Table 2
Input (x) 0.5 7 7 12 15
Output (y) 7 15 10 23 30
We already know that a function is a relation where each input or x-value of the X set has a unique y-value or output of the Y set.
In other words, we can not have duplicated inputs as there should be only 1 output for each input.
From Table 2, it is clear that:
- There is a duplicated input (repeated x value) i.e. x = 7 appears twice. And we can not have repeated input values.
As the input x = 7 is repeated multiple times, thus, the given table 2 does not represent a function.
Therefore, Table 2 does not represent a function.
Answer:
0.1057
Step-by-step explanation:
We solve using z score formula.
z = (x-μ)/σ, where
x is the raw score = 57mm
μ is the population mean = 52mm
σ is the population standard deviation = 4mm
z = 57 - 52/4
z = 1.25
Probability value from Z-Table:
P(x<57) = 0.89435
P(x>57) = 1 - P(x<57)
1 - 0.89435
= 0.10565
Approximately = 0.1057
The probability that the diameter of a selected bearing is greater than 57 millimeters is 0.1057
Answer:
i think the new points are
A(1,-2)
B(-2,-3)
C(4,5)
Step-by-step explanation:
i plugged it in
