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2 years ago

11

The Diagram below shows rectangle PLUM find the area of PLUM if entering answer as a decimal, round your final answer to the nea

rest hundredth. Please Help!

1 answer:

zhannawk [14.2K]2 years ago

4 0

Answer:

A = 75 units²

Step-by-step explanation:

6-8-10 triangle so PL = 10

For left triangle

6/8 = PM/10

PM = 60/8 = 7.5

A = PL•PM = 7.5(10) = 75

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Two-thirds of a number added to itself is 20. What is the number?

vivado [14]

Answer:

12

Step-by-step explanation:

2/3 x + x = 20

2/3 x + 3/3x = 20

5/3 x = 20 ... times 3/5 both sides

x = 12

check: 2/3 x 12 + 12 = 8 + 12 = 20

8 0

3 years ago

A gumball machine has 220 red gumballs. If the red gumballs are 50% of the total number of gumballs, how many gumballs are in

JulijaS [17]

Answer:

440

Explanation:

If 50% of the total gum balls are red which is 220, then the other 50% is 220.

5 0

3 years ago

Read 2 more answers

HELPPPP PLEASEEE IM BEGGING SOMEONE PLEASE PLEASE HELP

pychu [463]

Given:

The figure of a rhombus QRST.

To find:

A. The value of x.

B. The measure of angle RQP.

Solution:

A. We need to find the value of x.

We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.

$m\angle RPS=90^\circ$ [Right angle]

$(5x+15)^\circ=90^\circ$

$(5x+15)=90$

$5x=90-15$

$5x=75$

Divide both sides by 5.

$x=\dfrac{75}{5}$

$x=15$

Therefore, the value of x is 15.

B. We need to find the measure of angle RQP.

From the given figure, it is clear that

$m\angle RQP=(2x+3)^\circ$

Putting $x=15$ , we get

$m\angle RQP=(2(15)+3)^\circ$

$m\angle RQP=(30+3)^\circ$

$m\angle RQP=33^\circ$

Therefore, the measure of angle RQP is 33 degrees.

8 0

3 years ago

The altitude of an equilateral triangle is 9 inches. Find the perimeter of the triangle in inches.

Fiesta28 [93]

If we draw a perpendicular line from one of the vertices of the triangle we get 2 right angled triangles each with altitude 9 ins and vertex angle = 30 degrees. So:-

cos 30 = 9 /h where h = one of the sides of the equilateral triangle

h = 9 / cos 30 = 10.392 inches

Therefore the perimeter of the triangle = 3 * 10.392 = 31.1769 ins

Answer is 31.18 inches to the nearest hundredth.

5 0

3 years ago

What is the distance to the earth’s horizon from point P?<br><br> Express your answer as a decimal

rewona [7]

Answer:

The distance to the earth's horizon from point P is 216.2198187 mi, appriximately 216.22 mi

Step-by-step explanation:

This is a right triangle:

Hypotenuse: c=3959 mi + 5.9 mi → c=3964.9 mi

Leg 1: a=x=?

Leg 2: b=3959 mi

Using the Pytagorean theorem:

a^2+b^2=c^2

Replacing the known values:

(x)^2+(3959 mi)^2=(3964.9 mi)^2

Solving for x: Squaring:

x^2+15,673,681 mi^2=15,720,432.01 mi^2

Subtracting 15,673,681 mi^2 both sides of the equation:

x^2+15,673,681 mi^2-15,673,681 mi^2=15,720,432.01 mi^2-15,673,681 mi^2

x^2=46,751.01 mi^2

Square root both sides of the equation:

sqrt(x^2)=sqrt(46,751.01 mi^2)

x=216.2198187 mi

x=216.22 mi

3 0

3 years ago