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GrogVix [38]
3 years ago
10

Is visible light is a kind of electromagnetic wave

Physics
1 answer:
nata0808 [166]3 years ago
6 0

Visible light is a form of electromagnetic radiation. Visible light falls in the range of the EM spectrum between infrared and ultraviolet light. So I'd assume it is.

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Se lanza un cuerpo de 25 kg sobre un plano horizontal, con una velocidad de 20 m/s. Si el coeficiente de rozamiento es de 0,4 ca
Alex Ar [27]

Answer:

1. 98 N

2. 51.0 m

Explanation:

masa 25 kg

velocidad 20 m/s

coeficiente de rozamiento .4

<u>Fuerza de rozamiento:</u>

mu * N, where mu = coeficiente de rozamiento, N = fuerza normal

Calcula N:

F = ma = 25 * -9.8 = -245 N

F rozamiento = mu * N = .4 * -245 = -98 N

<u>Espacio que recorrerá:</u>

F rozamiento = ma

-98 = 25a

a = -3.92 de-aceleración de la fuerza

vf = 0 m/s

vf = at + vi

0 = -3.92t + 20

t = 5.10 seg

x = 1/2 at^2 + vi*t

  = 1/2 * -3.92 * 5.10^2 + 20*5.10

  = 51.0 m

 

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3 years ago
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6 0
4 years ago
Determine the thrust produced if 1.5 x 10^3 kg of gas exits the combustion chamber each second, with a speed of 4.00 x 10^3 m/s.
ozzi

Answer:

The thrust is 6\times 10^6\ N

Explanation:

Given that,

Mass of gas, m=1.5\times 10^3\ kg

The rate at which the gas is expelling, \dfrac{dv}{dt}=4\times 10^{3}\ m/s

We need to find the thrust produced by the gas.

We know that force is equal to the rate of change of momentum. So,

F=\dfrac{p}{t}

Also, p = mv

F=\dfrac{mv}{t}

So,

F=1.5\times 10^3\times 4\times 10^3\\\\F=6\times 10^6\ N

So, the thrust is 6\times 10^6\ N

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4 years ago
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3 years ago
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