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4 years ago

How have human factors contributed to climate change, and what evidence supports these factors?

Physics

2 answers:

lukranit [14]4 years ago

8 0

By factorys. Because the smoke that builds up from them

dimaraw [331]4 years ago

6 0

Humans and their inventions have hurt the environment. This has been tested and has shown that factories and other machines let out dangerous fumes into the atmosphere.

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A 0.676 m long section of cable carrying current to a car starter motor makes an angle of 57.7º with the Earth’s 5.29 x 10^−5T f

Studentka2010 [4]

Answer:

The current in the wire under the influence of the force is 216.033 A

Solution:

According to the question:

Length of the wire, l = 0.676 m

$\theta = 57.7^{\circ}$

Magnetic field of the Earth, $B_{E} = 5.29\times 10^{- 5} T$

Forces experienced by the wire, $F_{m} = 6.53\times 10^{-3} N$

Also, we know that the force in a magnetic field is given by:

$F_{m} = IB_{E}lsin\theta$

$I = \frac{F_{m}}{B_{E}lsin\theta}$

$I = \frac{6.53\times 10^{-3}}{5.29\times 10^{- 5}\times 0.676sin57.7^{\circ}$

I = 216.033 A

5 0

3 years ago

11. How many millimeters are in 4.511 meters?

Snezhnost [94]

Answer:

4511millimetres

Explanation:

6 0

4 years ago

Read 2 more answers

Which of the following is the same in all frames and reference?

Otrada [13]

B.Speed of light

The speed of light is used as a reference and is 3x10^8 m/s no matter what.

Hope this helps :)

7 0

3 years ago

Suppose two parallel-plate capacitors have the same charge Q, but the area of capacitor 1 is A and the area of capacitor 2 is 2

almond37 [142]

Answer:

V' = V/2

Explanation:

The voltage across a parallel plate capacitor is given as follows:

V = Q/C

where,

V = Voltage across capacitor

Q = Charge on Capacitor

C = Capacitance of Capacitor = A∈₀/d

Therefore,

V = Qd/A∈₀

where,

A = Area of plate

d = distance between plates

∈₀ = permittivity of free space

FOR CAPACITOR 1:

Q = Q

d = d

A = A

V = V

Therefore,

V = Qd/A∈₀ --------------- equation (1)

FOR CAPACITOR 2:

V' = ?

Q' = Q

d' = d

A' = 2A

Therefore,

V' = Q'd'/A'∈₀

V' = Qd/2A∈₀

V' = (1/2)(Qd/A∈₀)

using equation (1):

V' = V/2

8 0

3 years ago

A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied

Vika [28.1K]

We have that for the Question "A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied on the book, perpendicular to the wall, to prevent the book from slipping down the wal" it can be said that the minimum force that must be applied on the book is

F=44N

From the question we are told

A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied on the book, perpendicular to the wall, to prevent the book from slipping down the wal

Generally the equation for the Force is mathematically given as

$F=\frac{mg}{\mu}\\\\F=\frac{2*9.8}{0.45}\\\\$

F=44N

Therefore

the minimum force that must be applied on the book is

F=44N

For more information on this visit

brainly.com/question/23379286

8 0

3 years ago