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3 years ago

PLEASE HELP ME!!!! Like I have 8 assignments missing in math this is too stressful

Mathematics

2 answers:

melisa1 [442]3 years ago

7 0

Answer:

Step-by-step explanation:

5 x 3=15

Otrada [13]3 years ago

4 0

Answer:

Step-by-step explanation:

6 divided by 2 is 3 and 21 divided by 7 is also 3 so just multiply 5 by 3 and its 15

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The counting numbers are also called Integers

melisa1 [442]

Answer: Yes

Step-by-step explanation:

What is your question

8 0

3 years ago

Read 2 more answers

Question is in the image

pshichka [43]

Answer:

(x +3)^2 + (y -3)^2 = 3^2

Step-by-step explanation:

Your first task is to find the center.

The longest possible line of the circle goes from (-3,0) to (-3,6)

So the center is at the midpoint of these two points.

The midpoint is at (-3 - 3)/2 , (6+ 0)/2 or (-3,3)

That gives you the center of the circle.

So far what you have is

(x +3)^2 + (y -3)^2 = r^2

Now the distance of the center to the bottom point is (-3,3) to (-3,0)

r^2 = (x2 - x1)^2 + (y2 - y1)^2

x2 = - 3

x1 = - 3

y2 = 3

y1 = 0

r^2 = (-3 - -3)^2 + (3 - 0)^2

r^2 = 3^2

The entire answer is

(x +3)^2 + (y -3)^2 = 3^2

8 0

3 years ago

Linda throws a dart that hits the square shown below: A square is drawn. A circle of radius 9 units touches the sides of the squ

nataly862011 [7]

Probability helps us to know the chances of an event occurring. The probability of Linda's dart hitting the circle is 0.7857.

<h3>What is Probability?</h3>

The probability helps us to know the chances of an event occurring.

$\rm{Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}$

As it is given that the circle touches the sides of the square. therefore, the length of the side of the square is the diameter of the circle.

Now, in order to calculate the probability that the dart hits a point in the circle we need to calculate the area of the circle and the area of the square.

Area of the circle with a given radius of 9 units,

$\text{Area of the circle} = \pi r^2$

$\rm = \pi \times (9^2)\\\\= 81\pi\ units^2$

Area of the square with sides equal to the diameter of the circle,

$\rm \text{Area of square} = side^2$

$\rm = Diameter ^2\\\\= (2 \times radius)^2\\\\= (2 \times 9)^2\\\\= 18^2\\\\= 324\ units^2$

Now, the probability that the dart hits a point in the circle can be written as,

$\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}\\\\\\Probability=\dfrac{\text{Area of the circle}}{\text{Area of square}}\\\\\\Probability=\dfrac{81 \pi}{324} = 0.7857$