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GrogVix [38]
3 years ago
14

–6 < 2x – 4 < 4 solve the inequality

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
6 0

Answer:

The answer is

<h2>- 1 < x < 4</h2>

Step-by-step explanation:

<h3>- 6 < 2x - 4 < 4</h3>

First of all add 4 to both sides of the inequality to make 2x stand alone

That's

<h3>- 6 + 4 < 2x - 4 + 4 < 4 + 4 \\  - 2 < 2x < 8</h3>

Divide both sides of the inequality by 2 inorder to find x

That's

<h3>\frac{ - 2}{2}  <  \frac{2x}{2}  <  \frac{8}{2}</h3>

We have the final answer as

<h3>- 1 < x < 4</h3>

Hope this helps you

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3 years ago
Select the simplification that accurately explains the following statement.
lutik1710 [3]

Answer:

Option (b) is correct.

(2^\frac{1}{4} )^4=2^\frac{1}{4} \times 2^\frac{1}{4}\times 2^\frac{1}{4}\times 2^\frac{1}{4}=2^{(\frac{1}{4}+ \frac{1}{4}+ \frac{1}{4}+ \frac{1}{4} )}=2^{1}=2

Step-by-step explanation:

Given: (2^\frac{1}{4} )^4

We have too choose the correct simplification for the given statement.

Consider (2^\frac{1}{4} )^4

Using property of exponents, (a^m)^n=a^m\times a^m\times a^m\times ....\times (n\ times)

We have,

(2^\frac{1}{4} )^4=2^\frac{1}{4} \times 2^\frac{1}{4}\times 2^\frac{1}{4}\times 2^\frac{1}{4}

Again applying property of exponents  a^m\times a^m=a^{n+m}

We have,

(2^\frac{1}{4} )^4=2^{(\frac{1}{4}+ \frac{1}{4}+ \frac{1}{4}+ \frac{1}{4} )}

Simplify, we have,

(2^\frac{1}{4} )^4=2^{\frac{4}{4}}

we get,

(2^\frac{1}{4} )^4=2^{1}=2

Thus, (2^\frac{1}{4} )^4=2

Option (b) is correct.

   

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Step-by-step explanation:

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Step-by-step explanation:

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