We need to identify what "the nearest cent" is.
So!
AB.CD
That is a representation of a number using variables, but we'll just say it's for place values.
A is in the Tens Place
B is in the Ones Place
C is in the Tenths Place (1/10)
D is in the Hundredths Place (1/100
Since we are talking about money let's put it in relation to a dollar.
A is in the Ten Dollar Place
B is in the One Dollar Place
C is in the Tenth of a Dollar Place (1/10 of a dollar)
D is in the Hundredth of a Dollar Place (1/100 of a dollar)
So, what is 1/10 of a dollar?
What amount of money times 10, would get you 1 dollar. Or you can think of it as if you had 10 of one value of money and you got a dollar what is that? A dime.
Now, what is 1/100 of a dollar?
What amount of money times 100, would get you 1 dollar. 1 cent (Or it is sometimes called a penny).
So that means any number beyond the 1/100 of a dollar point (D) will be rounded. If it's the first number after the 1/100 of a dollar is greater than (or equal to) 5 then we round the cent value up. If it is less than 5 we round down.
$29.4983
So, 9 is our cent place. 8 is greater than 5, so we round 9 up. (Add 1. Since it is 9 it will carry over into the 1/10 of a dollar place)
Our answer is:
$29.50
The answer: 4
64’s common factors are 2 2 2 2 2 2
12’s common factors are 2 3 2
Find the factors that 64 and 12 have in common. The answer is 2 x 2= 4
Answer:
Column A Column B
1. x² + 6x + 8 x-3,x+2
2. x³ - 7x + 6 x+1, x+2, x+3
3. x³ - 2x² - 5x + 6 x-1, x+2, x-3
Step-by-step explanation:
Column A Column B
1. x² + 6x + 8 x-3,x+2
2. x³ - 7x + 6 x+1, x+2, x+3
3. x³ - 2x² - 5x + 6 x-1, x+2, x-3
Using Factor theorem we put values of x = ±1,±2,±3 in each of the polynomials unless we get a zero.
1. x² + 6x + 8
= 1+6(1) +8= 15
1. x² + 6x + 8
4+ 12+8 = 24
1. x² + 6x + 8
(-1)² + 6(-1)+ 8
= 1-6+8= 3
1. x² + 6x + 8
(-2)² + 6(-2)+ 8
= 4-12+8= 0
1. x² + 6x + 8
(3)²+ 6(3) +8
= 9+18+8 ≠ 0
1. x² + 6x + 8
(-3)²+ 6(-3) +8
= 9-18+8 =-1
For this polynomial we have x+2= 0 or x=-2, x-3= 0 , x=3
2. x³ - 7x + 6
1-7+6= 0
2. x³ - 7x + 6
(-1)³-7(-1) +6
= 13-1≠0
2. x³ - 7x + 6
(2)³-7(2) +6
= 8-14+6= 0
2. x³ - 7x + 6
(-2)³-7(-2) +6
= -8 +14+6
2. x³ - 7x + 6
(-3)³-7(-3) +6
= -27+21+6 = 0
For this polynomial we have x+1= 0 , x+2 = 0 and x+3= 0, or x=-1,-2,-3
3. x³ - 2x² - 5x + 6
(1)³-2(1)²-5(1)+6
= 0
3. x³ - 2x² - 5x + 6
(-1)³-2(-1)²-5(-1)+6
= -1 -2 +5+6
=8
3. x³ - 2x² - 5x + 6
(2)³-2(2)²-5(2)+6
= 8-8-10+6
=-4
3. x³ - 2x² - 5x + 6
(-2)³-2(-2)²-5(-2)+6
= -8-8+10+6
=0
3. x³ - 2x² - 5x + 6
(3)³-2(3)²-5(3)+6
= 27-18-15+6
=0
3. x³ - 2x² - 5x + 6
(-3)³-2(-3)²-5(-3)+6
= -27-18+15+6
=-14
For this polynomial we have x-1= 0 ,x+2=0, x-3= 0or x=1,-2,3
432 million, 540 times .20 equals 108, subtract 108 from 540 and you get your answer
