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Svetllana [295]
3 years ago
8

Simplify (65)2 O A. 670 O B. 67 C. 65 D. 63

Mathematics
1 answer:
Ket [755]3 years ago
8 0
130 If you multiply that’s what it would give you so I’m not sure what those answers are
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#89 will give brainliest for best answer!​
Lady_Fox [76]

Answer:

Median: 11

Range: 12

25th Percentile: 9

75th Percentile: 14

Interquartile Range: 5

Step-by-step explanation:

The median is the line in the 'middle' of the box. The range is the largest number minus the smallest number. 25th Percentile is the first line of the box, 75th is 3rd line. IQR is the 75th Percentile - 25th Percentile.

Hope this helps! :)

6 0
2 years ago
Which expression shows how to find the quotient of 4.8÷2?
xenn [34]

Answer:

[A] (4 ÷ 2)+(0.8 ÷ 2)

Step-by-step explanation:

Divide the 2 into each digit, which must be in the same spot it was before:

Knowing that 8 in 4.8 ⇒ 0.8

Thus, you can infer that [B] is wrong

You also infer that [D]  and [C] is wrong because 4 is a whole number.

Thus, that left us with [A] 4 ÷ 2+0.8 ÷ 2 which shows the quotient of 4.8 ÷ 2

Hence, [A] 4 ÷ 2+0.8 ÷ 2 is the answer.

<em>~Learn with Lenvy~</em>

5 0
2 years ago
Read 2 more answers
a) Which relationship is stronger, the relationship between GPA and AGE or the relationship between GPA and SAT score? Be sure t
Bezzdna [24]
GPA and SAT score. your age really has nothing to do with your Gpa. your Gpa is your grade point average, therefore it determines how well you're doing in school. you can have any Gpa at any age, depending on your abilities.
4 0
3 years ago
Each of the 20 employees in an office took a 60 point test on office safety. The test scores are listed in the table below. Whic
madam [21]

Answer:

There is no table

Step-by-step explanation:

But to construct a histogram, we use frequence on the y-axis and class boundaries on the x-axis

7 0
3 years ago
If SAT scores are normally distributed with a mean of 1518 and a standard deviation of 325, find the probability that a randomly
aliya0001 [1]
Mean, x_bar = 1518
Standard deviation, sigma = 325
Range required: 1550 ≤ X ≤ 1575

Z = (X - x_bar)/sigma

Z1 = (1550-1518)/325 ≈ 0.1
Z2 = (1575-1518)/325 ≈ 0.18

From Z tables,
P(Z1) = 0.5398
P(Z2) = 0.5714

P(1550≤X≤1575) = P(Z2) - P(Z1) = 0.5714 - 0.5398 = 0.0316

The correct answer is C.
3 0
3 years ago
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