<u>Step-by-step explanation:</u>
transform the parent graph of f(x) = ln x into f(x) = - ln (x - 4) by shifting the parent graph 4 units to the right and reflecting over the x-axis
(???, 0): 0 = - ln (x - 4)

0 = ln (x - 4)

1 = x - 4
<u> +4 </u> <u> +4 </u>
5 = x
(5, 0)
(???, 1): 1 = - ln (x - 4)

1 = ln (x - 4)

e = x - 4
<u> +4 </u> <u> +4 </u>
e + 4 = x
6.72 = x
(6.72, 1)
Domain: x - 4 > 0
<u> +4 </u> <u>+4 </u>
x > 4
(4, ∞)
Vertical asymptotes: there are no vertical asymptotes for the parent function and the transformation did not alter that
No vertical asymptotes
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transform the parent graph of f(x) = 3ˣ into f(x) = - 3ˣ⁺⁵ by shifting the parent graph 5 units to the left and reflecting over the x-axis
Domain: there is no restriction on x so domain is all real number
(-∞, ∞)
Range: there is a horizontal asymptote for the parent graph of y = 0 with range of y > 0. the transformation is a reflection over the x-axis so the horizontal asymptote is the same (y = 0) but the range changed to y < 0.
(-∞, 0)
Y-intercept is when x = 0:
f(x) = - 3ˣ⁺⁵
= - 3⁰⁺⁵
= - 3⁵
= -243
Horizontal Asymptote: y = 0 <em>(explanation above)</em>
The two shorter sides of triangle are 9 and 12. what is a possible length to make length of the third side to make the triangle acute with acuteT
Answer: Pythagorean Theorem Pieces of Right Triangles is not a justification for the proof.
Explanation : Here,
is a right triangle with sides a, b and c. Perpendicular CD forms right triangles BDC and CDA.
CD measures h units, BD measures y units, DA measures x units.
Draw an altitude from point C to Line segment AB Let segment BC = a segment CA = b, segment AB = c, segment CD = h, segment DB = y, segment AD = x,
y + x = c
a/c=y/a( Similarity theorem in triangles ABC and DBC )
------(1) (Cross Product Property)
Similarly,
(Similarity theorem in triangles ABC and ADC)---------(2)
(after adding equation (1) and (2) )
( By additional property of equality)
. ( because y + x=c)
Thus, it has been proved that except Pythagorean Theorem Pieces of Right Triangles we use all other properties.
90 words in 4 minutes is the same as 45 words in 2 minutes because you divide both sides by 2. 2 goes into 10, 5 times, so 45x5=225.
You can expect her to type 225 words in 10 minutes.
Let the total toys be x.
The first has (1/10)x = x/10
The third child has one more toys than the first = x/10 + 1
The fourth has double of the third: = 2* (x/10 + 1) = 2x/10 + 2
Since we know that the second child has 12 more toys than the first
Therefore the Second minus First = 12.
First let us find the second.
1st + 2nd + 3rd + 4th = x
x/10 + 2nd + (x/10 + 1) + (2x/10 + 2) = x
2nd + x/10 + x/10 + 1 + 2x/10 + 2 = x
2nd + x/10 + x/10 + 2x/10 + 1 + 2 = x
2nd + 4x/10 + 3 = x
2nd = x - 4x/10 - 3
2nd = 6x/10 - 3
But recall
2nd - 1st = 12
6x/10 - 3 - x/10 = 12
6x/10 - x/10 = 12 + 3
5x/10 = 15
5x = 15 * 10
x = 15*10 /5
x = 30
So there were 30 toys in all.