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MatroZZZ [7]
3 years ago
10

Select the expression that is equivalent to -4(3m - 5)

Mathematics
2 answers:
spin [16.1K]3 years ago
8 0

Step-by-step explanation:

-4(3m - 5) = -12m + 20

C.) -12m -(-20)

-12m + 20

Misha Larkins [42]3 years ago
5 0
Answer:

B

Explanation:

The answer to the original expression is -12 - 20.

And the answer to B, is -12 - 20.
-4 x 3 = -12
-4 x 5 = -20
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HELP with these questions
zlopas [31]

<u>Step-by-step explanation:</u>

transform the parent graph of f(x) = ln x        into f(x) = - ln (x - 4)  by shifting the parent graph 4 units to the right and reflecting over the x-axis

(???, 0): 0 = - ln (x - 4)

            \frac{0}{-1} = \frac{-ln (x - 4)}{-1}

            0 = ln (x - 4)

            e^{0} = e^{ln (x - 4)}

             1 = x - 4

          <u> +4 </u>  <u>    +4 </u>

             5 = x

(5, 0)

(???, 1): 1 = - ln (x - 4)

            \frac{0}{-1} = \frac{-ln (x - 4)}{-1}

            1 = ln (x - 4)

            e^{1} = e^{ln (x - 4)}

             e = x - 4

          <u> +4 </u>   <u>    +4 </u>

         e + 4 = x

          6.72 = x

(6.72, 1)

Domain: x - 4 > 0

                <u>  +4 </u>  <u>+4  </u>

               x       > 4

(4, ∞)

Vertical asymptotes: there are no vertical asymptotes for the parent function and the transformation did not alter that

No vertical asymptotes

*************************************************************************

transform the parent graph of f(x) = 3ˣ        into f(x) = - 3ˣ⁺⁵  by shifting the parent graph 5 units to the left and reflecting over the x-axis

Domain: there is no restriction on x so domain is all real number

(-∞, ∞)

Range: there is a horizontal asymptote for the parent graph of y = 0 with range of y > 0.  the transformation is a reflection over the x-axis so the horizontal asymptote is the same (y = 0) but the range changed to y < 0.

(-∞, 0)

Y-intercept is when x = 0:

f(x) = - 3ˣ⁺⁵

      = - 3⁰⁺⁵

      = - 3⁵

      = -243

Horizontal Asymptote: y = 0  <em>(explanation above)</em>

5 0
4 years ago
The two shorter sides of a triangle are 9 and 12. what is a possible length to make length of the third side to make the triangl
Paraphin [41]
The two shorter sides of triangle are 9 and 12. what is a possible length to make length of the third side to make the triangle acute with acuteT
6 0
3 years ago
ΔABC is a right triangle. Prove: a2 + b2 = c2 Right triangle BCA with sides of length a, b, and c. Perpendicular CD forms right
777dan777 [17]

Answer: Pythagorean Theorem Pieces of Right Triangles is not a justification for the proof.

Explanation : Here, \triangle ABC is a right triangle with sides a, b and c. Perpendicular CD forms right triangles BDC and CDA.

CD measures h units, BD measures y units, DA measures x units.

Draw an altitude from point C to Line segment AB Let segment BC = a segment CA = b, segment AB = c,  segment CD = h,  segment DB = y, segment AD = x,

y + x = c

a/c=y/a( Similarity theorem in triangles ABC and DBC )

a^2 = cy------(1) (Cross Product Property)

Similarly, b^2 = cx (Similarity theorem in triangles ABC and ADC)---------(2)

a^2 + b^2 = cy + cx(after adding equation (1) and (2) )

a^2 + b^2 = c(y + x)( By additional property of equality)

a^2 + b^2 = c^2. ( because y + x=c)

Thus, it has been proved that except Pythagorean Theorem Pieces of Right Triangles we use all other properties.

8 0
3 years ago
Read 2 more answers
Sara can type 90 words in 4 minutes.About how many words would you expect her to type in 10 minutes?
Alexus [3.1K]
90 words in 4 minutes is the same as 45 words in 2 minutes because you divide both sides by 2.  2 goes into 10, 5 times, so 45x5=225.
You can expect her to type 225 words in 10 minutes.
3 0
3 years ago
Four children have small toys. The first child has 1/10 of the toys, the second child has 12 more toys than the first, the third
GREYUIT [131]
Let the total toys be x.

The first has (1/10)x =  x/10


The third child has one more toys than the first =  x/10  + 1

The fourth has double of the third:  =  2* (x/10 + 1)  =  2x/10 + 2


Since we know that the second child has 12 more toys than the first

Therefore the Second  minus First = 12.


First let us find the second.

1st + 2nd + 3rd + 4th = x

x/10   +  2nd +  (x/10 + 1) + (2x/10 + 2) = x

2nd + x/10  + x/10 + 1 + 2x/10 + 2 = x

2nd + x/10 + x/10 + 2x/10 + 1 + 2  = x

2nd + 4x/10 + 3 = x

2nd = x - 4x/10 - 3

2nd =  6x/10  - 3

But recall

2nd - 1st = 12

6x/10 - 3 - x/10 = 12

6x/10 - x/10 = 12 + 3

5x/10 = 15

5x =  15 * 10

x  = 15*10 /5

x = 30

So there were 30 toys in all.
3 0
3 years ago
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