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1 year ago

Find the mean and median of these data: 2, 5, 13, 15, 19, 21.

1 answer:

3 0

The Arithmetic Mean and Median of the given set of data ( 2, 5, 13, 15, 19, 21 ) are 12.5 and 14 respectively.

<h3>What is Arithmetic mean?</h3>

Arithmetic mean is simply the average of a given set numbers. It is determined by dividing the sum of a given set number by their number of appearance.

Mean = Sum total of the number ÷ n

Where n is number of numbers

Median is the middle number in the data set.

Given the sets;

2, 5, 13, 15, 19, 21

n = 6

Mean = Sum total of the number ÷ n

Mean = (2 + 5 + 13 + 15 + 19 + 21) ÷ 6

Mean = 75 ÷ 6

Mean = 12.5

Median is the middle number in the data set.

Median = ( 13 + 15 ) ÷ 2

Median = 14

Therefore, the Arithmetic Mean and Median of the given set of data ( 2, 5, 13, 15, 19, 21 ) are 12.5 and 14 respectively.

Learn more about arithmetic mean here: brainly.com/question/13000783

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The number of typing errors made by a typist has a Poisson distribution with an average of two errors per page. If more than two

wlad13 [49]

Answer: 0.6767

Step-by-step explanation:

Given : Mean = $\lambda=2$ errors per page

Let X be the number of errors in a particular page.

The formula to calculate the Poisson distribution is given by :_

$P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}$

Now, the probability that a randomly selected page does not need to be retyped is given by :-

$P(X\leq2)=P(0)+P(1)+P(2)\\\\=(\dfrac{e^{-2}2^0}{0!}+\dfrac{e^{-2}2^1}{1!}+\dfrac{e^{-2}2^2}{2!})\\\\=0.135335283237+0.270670566473+0.270670566473\\\\=0.676676416183\approx0.6767$

Hence, the required probability :- 0.6767

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3 years ago

12. From a rope 68 m long, pieces of equal size are cut. If length of one piece is 4/14 m, find the number of such pieces.

otez555 [7]

Answer:

hope this helps (sorry for messy handwriting!)

Step-by-step explanation:

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2 years ago

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A thin tube stretched across a street counts the number of pairs of wheels that pass over it. A vehicle classified as type A wit

aliina [53]

Answer: All possible solutions would be

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Step-by-step explanation:

Let the number of vehicle of type A be 'x'.

Let the number of vehicle of type B be 'y'.

Since we have given that

Number of axles of type A = 2

Number of axles of type B = 9

After 2 hours, number of counts = 101

so, our equation becomes,

$2x+9y=101$

So, all possible solutions would be

(1,41), (8,33), (15,25), (22,17), (29,9), (36,1)

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2 years ago

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aivan3 [116]

Answer:

7,000

Step-by-step explanation:

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3 years ago

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sergeinik [125]

Answer:

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Step-by-step explanation:

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