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2 years ago

Find the mean and median of these data: 2, 5, 13, 15, 19, 21.

1 answer:

3 0

The Arithmetic Mean and Median of the given set of data ( 2, 5, 13, 15, 19, 21 ) are 12.5 and 14 respectively.

<h3>What is Arithmetic mean?</h3>

Arithmetic mean is simply the average of a given set numbers. It is determined by dividing the sum of a given set number by their number of appearance.

Mean = Sum total of the number ÷ n

Where n is number of numbers

Median is the middle number in the data set.

Given the sets;

2, 5, 13, 15, 19, 21

n = 6

Mean = Sum total of the number ÷ n

Mean = (2 + 5 + 13 + 15 + 19 + 21) ÷ 6

Mean = 75 ÷ 6

Mean = 12.5

Median is the middle number in the data set.

Median = ( 13 + 15 ) ÷ 2

Median = 14

Therefore, the Arithmetic Mean and Median of the given set of data ( 2, 5, 13, 15, 19, 21 ) are 12.5 and 14 respectively.

Learn more about arithmetic mean here: brainly.com/question/13000783

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Which equation is y= 2x ^2 - 8x +9 rewritten in vertex form.

tankabanditka [31]

<span>y= 2x ^2 - 8x +9

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3 years ago

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Step-by-step explanation:

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3 years ago

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3 years ago

Read 2 more answers

Find the area of each sector shown (the shaded section)

mihalych1998 [28]

Answer:

The area of the sector (shaded section) is 29.51 $m^{2}$ .

Step-by-step explanation:

Area of a sector = (θ ÷ 360) $\pi$ $r^{2}$

where θ is the central angle of the sector, and r is the radius of the circle.

From the diagram give, diameter of the circle is 26 m. So that;

r = $\frac{diameter}{2}$

= $\frac{26}{2}$ = 13 m

θ = 360 - (180 + 160)

= 360 - 340

= $20^{o}$

Thus,

area of the given sector = $\frac{20}{360}$ x $\frac{22}{7}$ x $(13)^{2}$

= $\frac{20}{360}$ x x $\frac{22}{7}$ x 169

= 29.5079

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3 years ago

The diameters of bolts produced in a machine shop are normally distributed with a mean of 5.725.72 millimeters and a standard de

suter [353]

Answer:

Top 5% is 5.84 milliters and the bottom 5% is 5.60 millimeters.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 5.72, \sigma = 0.07$