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3 years ago

Is 1.125 a rational number

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

5 0

Answer:

Yes, 1.125 is a rational number because it can be expressed as a fraction.

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F(-12) if f(x) = 2x + 15

Alenkinab [10]

Answer: $f(-12)=-9$

Step-by-step explanation:

We have the following function:

$f(x)=2x+15$

And we have to evaluate it when $x=-12$ , this means we have to substitute $x$ by $-12$ :

$f(-12)=2(-12)+15$

Solving:

$f(-12)=-24+15$

Finally:

$f(-12)=-9$

8 0

3 years ago

C- 14b= if c equals -7 and b equals 1/7

Andrew [12]

-7 -14(1/7)

remove parenthesis

14 * 1/7 = 2 (14/1 * 1/7 = 2/1 which we reduce to just 2)

-7 -2

-9

8 0

3 years ago

The following 5 keys are for the following 5 locked padlocks. Each key opens one and only one padlock. Different keys open diffe

Scilla [17]

${5}^{5}$

is the answer.

7 0

3 years ago

The length of a rectangle is 3 inches more than the width. The area is 10 square inches. Find the dimensions

mr_godi [17]

Answer:

Width = 2

Length = 5

Step-by-step explanation:

let A be the area of the rectangle

L be the length of the rectangle

w be the width of the rectangle

Formula: ‘area of a rectangle’

A = L × w

…………………………………………………

A = L × w

⇔ 10 = (w + 3) × w

⇔ 10 = w² + 3w

⇔ w² + 3w - 10 = 0

Solving the quadratic equation w² + 3w - 10 = 0 :

Δ = 3² - 4(1)(-10) = 9 - (-40) = 9 + 40 = 49

then √Δ = 7

$\Longrightarrow w=\frac{-b+\sqrt{\Delta } }{2a} =\frac{-3+7}{2} =2$

$or\ w=\frac{-b-\sqrt{\Delta } }{2a} =\frac{-3-7}{2} =-5$

-5 is not valid ,because w represents the width

which must be a positive number

Then w = 2

Conclusion:

Width = 2

Length = 2 + 3 = 5

6 0

2 years ago

Prove: If n is a positiveinteger and n2 is divisible by 3, then n is divisible by3.

notka56 [123]

Answer:

If $n^2$ is divisible by 3, the n is also divisible by 3.

Step-by-step explanation:

We will prove this with the help of contrapositive that is we prove that if n is not divisible by 3, then, $n^2$ is not divisible by 3.

Let n not be divisible by 3. Then $\frac{n}{3}$ can be written in the form of fraction $\frac{x}{y}$ , where x and y are co-prime to each other or in other words the fraction is in lowest form.

Now, squaring

$\frac{n^2}{9} = \frac{x^2}{y^2}$

Thus,

$n^2 = \frac{9x^2}{y^2}$

$\frac{n^2}{3} = \frac{3x^2}{y^2}$

It can be clearly seen that the fraction $\frac{3x^2}{y^2}$ is in lowest form.

Hence, $n^2$ is not divisible by 3.

Thus, by contrapositivity if $n^2$ is divisible by 3, the n is also divisible by 3.

5 0

3 years ago