You can try finding the roots of the given quadratic equation to get to the solution of the equation.
There are two solutions to the given quadratic equation
<h3>How to find the roots of a quadratic equation?</h3>
Suppose that the given quadratic equation is 
Then its roots are given as:
<h3>How to find the solution to the given equation?</h3>
First we will convert it in the aforesaid standard form.
Thus, we have
a = 1. b = -114, c = 23
Using the formula for getting the roots of a quadratic equation,
Thus, there are two solutions to the given quadratic equation
Learn more here about quadratic equations here:
brainly.com/question/3358603
Answer:
let the numbers be xy
general form of the number =10x+y
sum of digits of a number =14
x+y=14………[1]
if 18 is added to the number, then digits are interchanged
10x+y+18=10y +x
9x-9y=-18
X-y=-2………[2]
the linear equations are 1) x+y=14
2) X-y=-2
adding [1],[2]
2x=12
x=6
x+y=14
y=14-x
y=14-6
y=8
there fore the number =10*6+8
=68
check:-
1)6+8=14
2)68+18=86
I hope this helped!
Step-by-step explanation:
Assume that
a and b = the two legs of the right triangle.
c = the hypotenuse.
The area of the right triangle is 750 yd², therefore
(1/2)*a*b = 750
ab = 1500 (1)
The perimeter is 150yd, therefore
a + b + c = 150 (2)
Let the side fenced with wood be a, at $5/yd. Sides b and c are fenced with steel at $10/y. The total cost is $1200, therefore
5a + 10b + 10c = 1200
or
a + 2b + 2c = 240 (3)
From (2), obtain
c = 150 - a - b (4)
Substitute (4) into (3)
a + 2b + 2(150 - a - b) = 240
-a + 300 = 240
a = 60
From (1), obtain
60b = 1500
b = 25
From (4), obtain
c = 150 - 60 - 25 = 65
Answer:
A. The length of the leg fenced with wood is 60 yd.
B. The length of the leg fenced with steel is 25 yd.
Each person has 4 guavas (12 divided by 3 is 4)
Answer: 1) 5040 and 2) 165
Step-by-step explanation:
1) Here total number of letters = 10
The number of permutations that can be formed using 4 letters at a time
= P (10, 4)
= 
= 
= 
= 
= 10 × 9 × 8 × 7
= 5040
2) Here the total number of machine = 11
The different combinations of machines can Geoff choose from to use
= 
= 
= 
= 
= 11 × 5 × 3
= 165
