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rewona [7]
2 years ago
13

N − 32 5 = 10 help plz

Mathematics
2 answers:
Keith_Richards [23]2 years ago
4 0

Answer:

n=335

Step-by-step explanation:

Soloha48 [4]2 years ago
3 0

Answer:

Step-by-step explanation:

Here you go mate

Step 1

n − 325 = 10  equation

Step 2

n − 325 = 10  simplify by adding 325 to both sides

Answer

n=335

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3 years ago
51/68 in simplest form
yanalaym [24]

Answer:3/4

Step-by-step explanation:

3 0
3 years ago
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4. Identify the graph of the solution set of 9 > 3 + 2x.
Ray Of Light [21]

Answer:

A

Step-by-step explanation:

9 > 3 + 2x

6 > 2x

3 > x

or

x < 3

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2 years ago
Find four distinct complex numbers (which are neither purely imaginary nor purely real) such that each has an absolute value of
Luda [366]

Answer:

  • 0.5 + 2.985i
  • 1 + 2.828i
  • 1.5 + 2.598i
  • 2 + 2.236i

Explanation:

Complex numbers have the general form a + bi, where a is the real part and b is the imaginary part.

Since, the numbers are neither purely imaginary nor purely real a ≠ 0 and b ≠ 0.

The absolute value of a complex number is its distance to the origin (0,0), so you use Pythagorean theorem to calculate the absolute value. Calling it |C|, that is:

  • |C| = \sqrt{a^2+b^2}

Then, the work consists in finding pairs (a,b) for which:

  • \sqrt{a^2+b^2}=3

You can do it by setting any arbitrary value less than 3 to a or b and solving for the other:

\sqrt{a^2+b^2}=3\\ \\ a^2+b^2=3^2\\ \\ a^2=9-b^2\\ \\ a=\sqrt{9-b^2}

I will use b =0.5, b = 1, b = 1.5, b = 2

b=0.5;a=\sqrt{9-0.5^2}=2.958\\ \\b=1;a=\sqrt{9-1^2}=2.828\\ \\b=1.5;a=\sqrt{9-1.5^2}=2.598\\ \\b=2;a=\sqrt{9-2^2}=2.236

Then, four distinct complex numbers that have an absolute value of 3 are:

  • 0.5 + 2.985i
  • 1 + 2.828i
  • 1.5 + 2.598i
  • 2 + 2.236i
4 0
3 years ago
If m&lt;3 = 54° find each measure.
oee [108]

Answer:

m<15

Step-by-step explanation:

m<15 promise ko heheh

8 0
2 years ago
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