The force the same object will exert if it accelerates at a rate of 7 m/s² is 35N
From the question,
We are to determine the force the object will exert.
From the information,
Newton’s Second Law of Motion states that the acceleration of an object is directly proportional to the force exerted on the object
Let acceleration be a
and
Force be F
Then we can write that,
F ∝ a
Then,
Introducing the constant, mass, m
We get
F = ma
Now, we will determine the mass of the object
F = 15 N
a = 3 m/s²
Putting the parameters into the formula, we get
15 = m × 3
∴ m = 15 ÷ 3
m = 5 kg
The mass of the object is 5 kg.
Now, to determine the force the same object will exert if it accelerates at a rate of 7 m/s²
That is,
a = 7 m/s²
and
m = 5 kg
Putting the parameters into the formula, we get
F = 5 × 7
F = 35 N
Hence, the force the same object will exert if it accelerates at a rate of 7 m/s² is 35N
Learn more here: brainly.com/question/13590154
90 volume because 3 multiples by 30 = 90
Hello!
To find how much chocolate Adi and Suresh receives, you need to convert the percentage to a decimal, then you multiply that decimal by the total number of chocolates, which is 20.
To convert percentages to decimals, divide the percentage by 100, and remove the percentage.
60% / 100 = 0.60
20% / 100 = 0.20
Then, we multiply 0.60 and 0.20 by 20.
0.60 x 20 = 12
0.40 x 20 = 8
Therefore, Adi gets 12 chocolates and Suresh gets 8 chocolates.
Refer to the attachment for step by step explaination.
Answer: [0, 396]
Step-by-step explanation:
The domain is the acceptable values of x in the function. In this case, x = t, the number of tiles. If you think about it, the minimum number of tiles is 0 (you can't have a negative number of tiles), and the maximum number of tiles is 44 (you only have 44 tiles). So, the domain for this function is from 0 to 44.
0 to 44 written in interval notation is [0,44].
The range is the acceptable values of y in the function. In this case, y = A, the area given. A(t) = 9t, so you can use the acceptable values of t to get the range. Again, the minimum area is 0 because you can't have negative area. To find the maximum area, plug in the maximum number of tiles: 9.
A(t) = 9t
A = 9(44)
A = 396
With the maximum number of tiles, 44, the area you get is 396 cm². Therefore, the acceptable values of A are from 0 to 396.
0 to 396 written in interval notation is [0, 396].
