It’s a 75 percent decrease
Assume that the data for both movies and basketball games are normally distributed.
Therefore, the median and the mean are assumed equal.
The standard deviation, σ, is related to the interquartile range by
IQR = 1.35
From the data, we can say the following:
Movies:
Range = 150 - 60 = 90 (approx)
Q1 = 62 (approx), first quartile
Q3 = 120 (approx), third quartlie
Q2 (median) = 90 (approx)
IQR = Q3 - Q1 = 58
σ = IQR/1.35 = 58/1.35 = 43
Basketball:
Range = 150 - 90 = 60 approx
Q1 = 95 (approx)
Q3 = 145 (approx)
Q2 = 125 (approx)
IQR = 145 - 95 = 50
σ = 50/1.35 = 37
Test the given answers.
A. The IQRs are approximately equal, so they are not good measures of spread. This is not a good answer.
B. The std. deviation is a better measure of spread for basketball. This is not a good answer.
C. IQR is not a better measure of spread for basketball games. This is not a good answer.
D. The standard deviation is a good measure of spread for both movies and basketball. This is the best answer.
Answer: D
Answer:
1.9
Step-by-step explanation:
you divide 12 by 2 then divided that by pi
Answer:
y = x^2 +6x +8
Step-by-step explanation:
The vertex is (-3, -1), and the vertical scale factor is 1. (You can tell this because the graph goes up 1 unit for 1 unit either side of the vertex.) So, the vertex form of the equation is ...
y = (x +3)^2 -1 . . . . . . . . . vertex form; sometimes called standard form
Expanding this, we get ...
y = x^2 +6x +8 . . . . . . . . also called the standard form equation
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<em>Comment on standard form</em>
There are different versions of "standard form" depending on what you're concerned with and where you are. Please consult your text or other reference material for the version of standard form you need. (The attachments show the conflict with respect to quadratic equations.)
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<em>Comment on the graph</em>
The purpose of the graph attached is to show that the equation we propose produces the same curve as the one given.
