Answer:
The ratio of the number of atoms of gold and silver in the ornament is 197 : 1080.
Explanation:
Let the mass of silver ornament be x.
Mass of gold polished on an ornament = 1% of x= 0.1 x
Moles of silver =
Number of atoms = 
Where : 
= Avogadro number
Moles of gold =
Silver atoms =
Gold atoms =
The ratio of the number of atoms of gold and silver in the ornament:
= 197 : 1080
False. A buffering solution consists of a WEAK acid such as CH3COOH, C5H5N, or ammonia. <span>A buffering solution resists pH change upon the addition of an acidic or basic components. It can neutralize little amounts of added acid or base, thus maintaining the pH of the solution relatively stable. The correct answer is letter "B. false"</span>
Answer: ZnS
Explanation: usually salts of alkali metals are well soluble in water.
Also most nitrates are well soluble.
Sulfides of transition metals are generally insoluble in water
The absorbance reported by the defective instrument was 0.3933.
Absorbance A = - log₁₀ T
Tm = transmittance measured by spectrophotometer
Tm = 0.44
Absorbance reported in this equipment = -log₁₀ (0.44) = 0.35654
True absorbance can be calculated by true transmittance, Tm = T+S(α-T)
S = fraction of stray light = 6%= 6/100 = 0.06
α= 1, ideal case
T = true transmittance of the sample
Tm = T+S(α-T)
now, T= Tm-S/ 1-S = 0.44-0.06/ 1-0.06 = 0.404233
therefore, actual reading measured is A = -log₁₀ T = -log₁₀ (0.404233)
i.e; 0.3933
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In order to compute the total hydrogen atoms present, we must first write the molecular formulas of ammonia and water to know how many hydrogen atoms are present in each molecule.
Water - H₂O; so 2 hydrogen atoms per molecule of water
Ammonia - NH₃; so 3 hydrogen atoms per molecule of ammonia
Total hydrogen atoms = 2 * molecules of water + 3 * molecules of ammonia
H atoms = 2 * 1.5 x 10²⁵ + 3 * 8.2 x 10²⁴
H atoms = 5.46 x 10²⁵
There are a total of 5.46 x 10²⁵ hydrogen atoms in the solution
