Answer:
Absolute zero is the lowest limit of the thermodynamic temperature scale, a state at which the enthalpy and entropy of a cooled ideal gas reach their minimum value, taken as zero kelvin.
Answer:
The answer to your question is P = 0.18 atm
Explanation:
Data
mass of O₂ = 0.29 g
Volume = 2.3 l
Pressure = ?
Temperature = 9°C
constant of ideal gases = 0.082 atm l/mol°K
Process
1.- Convert the mass of O₂ to moles
16 g of O₂ -------------------- 1 mol
0.29 g of O₂ ---------------- x
x = (0.29 x 1)/16
x = 0.29/16
x = 0.018 moles
2.- Convert the temperature to °K
Temperature = 9 + 273 = 282°K
3.- Use the ideal gas law ro find the answer
PV = nRT
-Solve for P
P = nRT/V
-Substitution
P = (0.018 x 0.082 x 282) / 2.3
-Simplification
P = 0.416/2.3
-Result
P = 0.18 atm
The answer for the following questions is explained below.
Explanation:
The two variables that affect kinetic energy are:
- mass and
- velocity
- velocity - The faster an object moves,the more the kinetic energy it has.
- mass - Kinetic energy increases as mass increases
The kinetic energy of an object depends on both its mass and its velocity
Kinetic energy increases as mass increases
For example,think about rolling a bowling ball and a golf ball down a bowling lane at same velocity
Here,the bowling ball has more mass than the golf ball
Therefore you use more energy to roll the bowling ball than to roll the golf ball
The bowling ball is more likely to knock down the pins because it has more kinetic energy than the golf ball
Answer:
moles = 36/180 = 0.2 moles
molarity = 0.2/2 = 0.1 mol/dm3
Moles of gas = 0.369
<h3>Further explanation</h3>
Given
P = 2 atm
V = 5.3 L
T = 350 L
Required
moles of gas
Solution
Ideal gas Law
Avogadro's law : at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles
moles of O₂ = 45% x 0.369 = 0.166
moles of Ar = 12% x 0.369 = 0.044
moles of N = 43% x 0.369 = 0.159
