Answer:
if i consider this reaction
Fe2O3+ 3CO---》2Fe+ 3CO2
so let's calculate first moles of Fe2O3 i.e. = 256/159.69= 1.6 moles
So the one moles of Fe2O3 is forming three moles of CO2
hence 1.6 moles will form 4.8 moles of CO2
one mole of CO2 is 44 g so 4.8 moles of Co2 is 44×4.8= 211.2 g
so the conclusion is 211.2 g of CO2 can be produced from 256 g Fe2O3!!
i d k it's right or wrong but i tried my best :)
I did this when I was younger
Answer:
80mL
Explanation:
Step 1:
Data obtained from the question.
Initial Volume (V1) = 40mL
Initial temperature (T1) = –123°C
Final temperature (T2) = 27°C
Final volume (V2) =..?
Step 2:
Conversion of celsius temperature to Kelvin temperature.
T(K) = T(°C) + 273
Initial temperature (T1) = –123°C =
–123°C + 273 = 150K
Final temperature (T2) = 27°C = 27°C + 273 = 300K
Step 3:
Determination of the final volume.
This can be obtained as follow:
V1/T1 = V2/T2
Initial Volume (V1) = 40mL
Initial temperature (T1) = 150K
Final temperature (T2) = 300
Final volume (V2) =..?
V1/T1 = V2 /T2
40/150 = V2 /300
Cross multiply
150 x V2 = 40 x 300
Divide both side by 150
V2 = (40 x 300) /150
V2 = 80mL
Therefore, the new volume of the gas is 80mL
Answer:
This is not accurate we dont know what your asking us?
Explanation:
Answer:
11.19% hydrogen and 88.81% oxygen
Explanation:
