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elixir [45]
3 years ago
12

How are scientist able to protect people from tornadoes

Chemistry
1 answer:
marusya05 [52]3 years ago
7 0
They cant physically. But what they can do is predict the patterns within the weather and how the outcome will be
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2Na(s) + 2H,O(l) — 2NaOH(?) + H, (g)<br> 0 what is the missing symbol
Klio2033 [76]

Answer:

the symbol that is missing might be 2.

Explanation:

I am not 100% on this, so correct me if I am wrong.

3 0
2 years ago
why does ice float on water? the temperature of ice is lower than the temperature of water. the temperature of water and ice are
Andrew [12]
The density of ice is less than the density of water.

Fun fact: Water is the only known liquid that has this change it density.
4 0
3 years ago
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Identify the products in the following chemical resction 2NaHCO3 + CaCI2 --&gt; CaCO3 + CO2 + 2NaCI + H2O​
Radda [10]

the products are:

CaCO3 Calcium Carbonate

CO2 carbon dioxide

NaCI Sodium chloride

H2O​ Water

8 0
3 years ago
Can some one please help me with this organic chemistry question?
const2013 [10]
I think it is gauche.

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4 0
3 years ago
He rate constant of a reaction is 4.55 × 10−5 l/mol·s at 195°c and 8.75 × 10−3 l/mol·s at 258°c. what is the activation energy o
Xelga [282]

Answer : The activation energy of the reaction is, 17.285\times 10^4kJ/mole

Solution :  

The relation between the rate constant the activation energy is,  

\log \frac{K_2}{K_1}=\frac{Ea}{2.303\times R}\times [\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = initial rate constant = 4.55\times 10^{-5}L/mole\text{ s}

K_2 = final rate constant = 8.75\times 10^{-3}L/mole\text{ s}

T_1 = initial temperature = 195^oC=273+195=468K

T_2 = final temperature = 258^oC=273+258=531K

R = gas constant = 8.314 kJ/moleK

Ea = activation energy

Now put all the given values in the above formula, we get the activation energy.

\log \frac{8.75\times 10^{-3}L/mole\text{ s}}{4.55\times 10^{-5}L/mole\text{ s}}=\frac{Ea}{2.303\times (8.314kJ/moleK)}\times [\frac{1}{468K}-\frac{1}{531K}]

Ea=17.285\times 10^4kJ/mole

Therefore, the activation energy of the reaction is, 17.285\times 10^4kJ/mole

8 0
3 years ago
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