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KengaRu [80]
4 years ago
12

At that volume is measured to be 755 mm of Hg. If the lungs are compressed to a newA healthy male adult has a lung capacity arou

nd 6.00 liters. The pressure in the lungs volume of 3.81 liters, what would be the new pressure in the lungs? What would happen to the air in the lungs?
Chemistry
1 answer:
Licemer1 [7]4 years ago
6 0

Answer:

1188.976 mmHg

Explanation:

Initial pressure P1= 755 mmHg

Initial volume V1 = 6.00 litres

Final volume V2 = 3.81 litres

Final pressure P2= the unknown

Now applying Boyle's Law,we have;

P1V1 = P2V2

Since P2 is the unknown then it has to be made the subject of the formula.

P2=P1V1/ V2

P2= 755 × 6.00/ 3.81

P2= 1188.976 mmHg

Therefore, the new pressure is; 1188.976 mmHg

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<h3>What is pH of solution?</h3>

The pH of a solution is defined as the logarithm of the reciprocal of the hydrogen ion concentration  [H+] of the given solution.

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