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KengaRu [80]
4 years ago
12

At that volume is measured to be 755 mm of Hg. If the lungs are compressed to a newA healthy male adult has a lung capacity arou

nd 6.00 liters. The pressure in the lungs volume of 3.81 liters, what would be the new pressure in the lungs? What would happen to the air in the lungs?
Chemistry
1 answer:
Licemer1 [7]3 years ago
6 0

Answer:

1188.976 mmHg

Explanation:

Initial pressure P1= 755 mmHg

Initial volume V1 = 6.00 litres

Final volume V2 = 3.81 litres

Final pressure P2= the unknown

Now applying Boyle's Law,we have;

P1V1 = P2V2

Since P2 is the unknown then it has to be made the subject of the formula.

P2=P1V1/ V2

P2= 755 × 6.00/ 3.81

P2= 1188.976 mmHg

Therefore, the new pressure is; 1188.976 mmHg

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Capillarity , Adhesion and cohesion . The unique property of water enable life to exist . The most important property of water is movement of materials due to water , maintenance and growth and reproduction .

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How many calories of heat are required to raise the temperature of 1.00kg of water from 10.2 degrees Celsius to 26.8 degrees Cel
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Explanation:

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Q=mcΔT

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Jean and her mother were taking a walk when they saw the two rocky outcrops in the diagram below.
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A chemist adds of a M zinc nitrate solution to a reaction flask. Calculate the mass in grams of zinc nitrate the chemist has add
weqwewe [10]

corrected question: A chemist adds 135mL of a 0.21M zinc nitrate solution to a reaction flask. Calculate the mass in grams of zinc nitrate the chemist has added to the flask. Round your answer to significant digits.

Answer:

5.37g

Explanation:

0.21M means ; 0.21mol/dm³

1dm³=1L , so we can say 0.21mol/L

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