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Finger [1]
3 years ago
11

PLEASE HELPP!!!!!!

Mathematics
1 answer:
Makovka662 [10]3 years ago
5 0

Answer:

see explanation!

Step-by-step explanation:

Line N

  • A set of points where the coordinates of each point have a sum of 2

Line M

  • A set of points where the y-coordinates of each point is 10 less than its x-coordinate

Any coordinate on N has a sum of 2.

Any coordinate on M has a y that is 10 less than the x.

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Given f(x)=7(9−x)−4, what is the value of f(−1) ?<br><br> Enter the answer in the box.
NeX [460]

Solution:

f(x) = 7(9 - x) - 4

f(-1) = 7(9 - (-1)) - 4

f(-1) = 7(10) - 4

f(-1) = 70 - 4

f(-1) = 66

Best of Luck~

4 0
3 years ago
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You buy the same number of brushes, rollers and paint cans. Write an expression in simples form that represents the total amount
jeyben [28]
T= 21.79x + 3.99x + 6.89x where t is the total cost and x is the number of brushes/rollers/paint cans you buy. You don't need a different variable for each item because you buy the same amount of each.
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3 years ago
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Evaluate the expression when m=32 and n=6. m/4+n
babunello [35]

Answer:

14

Step-by-step explanation:

32 divided by 4 is 8

8 plus 6 is 14

soooo 14 xd

6 0
3 years ago
Fourth degree and a single zero of -3
Darya [45]

The degree of a polynomial is the highest power of the polynomial.

The polynomial is \mathbf{P(x) = (x + 3)^4}

The degree is given as:

\mathbf{n = 4}

The zero is given as:

\mathbf{x = -3}

Add 3 to both sides

\mathbf{x  + 3= 0}

From the question, we understand that the polynomial has a single zero.

So, the polynomial is:

\mathbf{P(x) = (x + 3)^n}

Substitute 4 for n

\mathbf{P(x) = (x + 3)^4}

Hence, the polynomial is \mathbf{P(x) = (x + 3)^4}

Read more about polynomials at:

brainly.com/question/11536910

3 0
3 years ago
Show whether or not y=x+3 is tangential to the curve y^2=x​
wolverine [178]

The line y = x + 3 has slope 1, so we look for points on the curve where the tangent line, whose slope is dy/dx, is equal to 1.

y² = x

Take the derivative of both sides with respect to x, assuming y = y(x) :

2y dy/dx = 1

dy/dx = 1/(2y)

Solve for y when dy/dx = 1 :

1 = 1/(2y)

2y = 1

y = 1/2

When y = 1/2, we have x = y² = (1/2)² = 1/4. However, for the given line, when y = 1/2, we have x = y - 3 = 1/2 - 3 = -5/2.

This means the line y = x + 3 is not a tangent to the curve y² = x. In fact, the line never even touches y² = x :

x = y²   ⇒   y = y² + 3   ⇒   y² - y + 3 = 0

has no real solution for y.

3 0
2 years ago
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