D=event that chip selected is defective
d=event that chip selected is NOT defective
Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154
Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20
Answer:
6/1
Step-by-step explanation:
Both 18 and 3 can be divided by 3
18 divided by 3 = 6
3 divided by 3 = 1
So the ratio is 6 : 1
So the fraction is 6/1
Answer: Right angled triangles and parallelograms; Pythagorean triplets, triangles meet maths; Shadows and right triangles (radius of the Earth). The right ...
Step-by-step explanation:
Step-by-step explanation:
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