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3 years ago

Help me plz I beg you

Mathematics

1 answer:

scZoUnD [109]3 years ago

4 0

The answer would be C. We know that d is equal to the initial depth of a lake. The two given initial depths are 58 feet and 53 feet, so we know that one of the equations must be either d=58 or d=53. Because there only C has either one of those, d=58, we know that it must be the answer.

To find the other equation, it is just a linear function for the other lake. The y-intercept, or initial value, is 53, so in the equation y=mx+b, it is the b value. The slope, or m value, is 3 feet, so you have y=d=3x+53.

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PLEASE HELP WITH THIS ONE AS WELL! I’m struggling with Transcendental Functions!

Svetach [21]

$h(x)=20e^{kx}$

a. If $h(1)=20$ , then $20=20e^k\implies e^k=1\implies k=0$ .

b. If $h(1)=40$ , then $40=20e^k\implies e^k=2\implies k=\ln2$ , so that $2k+1=2\ln2+1$ .

c. If $h(1)=10$ , then $10=20e^k\implies e^k=\dfrac12\implies k=-\ln2$ , so that $k-3=-\ln2-3$ .

3 0

3 years ago

Evaluate f(-2) = -3x² - 2x

Delvig [45]

Answer:

-2F=7x

Step-by-step explanation:

F*-2= -2F 3x*3x=9x

-2F=9x-2x

8 0

2 years ago

I = Prt

Olegator [25]

Answer:

$r=3.5\%$

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=5\ years\\ P=\$1,200\\ I=\$210\\r=?$

substitute in the formula above

$210=1,200(5r)$

solve for r

$r=210/6,000$

$r=0.035$

convert to percentage (multiply by 100)

$r=3.5\%$

6 0

3 years ago

[20 points] -x + 4 = 9

sveta [45]

Answer: x = -5

Step-by-step explanation:

-x + 4 = 9

-4 -4

-x = 5

divide by -1 on both sides

x = -5

4 0

2 years ago

Read 2 more answers

In a random sample of 8 people, the mean commute time to work was 36.5 minutes and the standard deviation was 7.4 minutes. A 98%

ANEK [815]

Answer:

Step-by-step explanation:

Given that

Sample size = n = 8: sample mean = 36.5 and s = sample std dev = 7.4 minutes

98% CI using t = (28.7, 44.3) with margin of error as 7.8

Now if sigma = population std dev is known we use Z critical value

Margin of error = 2.33*8.7/\sqrt 8 = 7.167

CI = (36.5 ±7.167)

This is not wider than that used using t distribution

The margin of error of u is ___7.167

98% confidence interval using the standard normal distribution is (29.333__,43.667__)

d)the confidence interval found using the standard normal distrubution is narrower than the confidence interval found using the students t-distribution

3 0

3 years ago