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3 years ago

Help me plz I beg you

Mathematics

1 answer:

scZoUnD [109]3 years ago

4 0

The answer would be C. We know that d is equal to the initial depth of a lake. The two given initial depths are 58 feet and 53 feet, so we know that one of the equations must be either d=58 or d=53. Because there only C has either one of those, d=58, we know that it must be the answer.

To find the other equation, it is just a linear function for the other lake. The y-intercept, or initial value, is 53, so in the equation y=mx+b, it is the b value. The slope, or m value, is 3 feet, so you have y=d=3x+53.

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5/7 - 3/2 in simplest form HELP ASAP

IgorC [24]

$\frac{5}{7} \: - \: \frac{3}{2}$

First, we find the <u>lowest common denominator</u> which is "14", we put it in the common numerator.

$\frac{10 \: - \: 21}{14}$

We subtract the numbers.

$\boxed{ \bold{- \frac{11}{14} }}$

<h3><em><u>MissSpanish</u></em></h3>

4 0

1 year ago

Read 2 more answers

Partial product of 8.6x9.2

Kisachek [45]

8.6*9.2=79.12

Hope this helps!

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2 years ago

What's 93 divided by 4 and need work to prove that I did it

luda_lava [24]

93/4

9/4=2r1

13/4=4r1

10/4=2r2

20/5=4

=23.25

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3 years ago

A weather report said there is a 60% chance of rain on Monday, and a 30% chance of rain on Tuesday. Based on the report, what is

sergey [27]

Answer:

The answer is 18 percent, or 9/50.

Step-by-step explanation:

We first convert the chance of rain on Monday into a fraction.

60%=60/100=3/5.

We then convert the chance of rain on Tuesday into a fraction.

30%=30/100=3/10.

Because the two events are independent(i.e. If it rains on Tuesday doesn't depend on if it rains on Monday) we multiply them together to get the probability they both happen. That chance is:

3/5 * 3/10=(3*3)/(5*10)=9/50(fraction form)=18/100=18%(percent form)

5 0

2 years ago

A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from thi

SVETLANKA909090 [29]

Complete question:

Consider a class of 20 students consisting of 5 sophomores, 8 juniors, and 7 seniors. A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from this class, keeping track (in order) of the level of the student that he gets.

1a. How many possible outcomes are in the sample space S? (An outcome is a 5- tuple of students.)

Let A2 denote the event that exactly 2 of the selected students are sophomore, A5 denote the event that exactly 5 of the selected students are the juniors, and A4 denote the event that exactly 4 of the selected students are seniors.

1b. Find the probabilities of each of these three events. A2, A5, A4

1c. Do the events A2, A5, A4 constitute a partition of the sample space?

Answer:

Given:

n = 20

a) The possible outcome in the sample space,S, =

ⁿCₓ = ²⁰C₅

$= \frac{20!}{(20-5)! 5!)}$