Answer:
See below.
Step-by-step explanation:
a. See pic below.
b. Yes because it passes the vertical line test. Any vertical line moving horizontally across the graph intersects only one point on the graph at a time.
c.
Domain: all real numbers
Range: all real numbers greater than or equal to 4
d.
Domain: all real numbers greater than or equal to 4
Range: all real numbers
e.
See pic below.
f. No because it does not pass the vertical line test.
Answer:
$76.50
Step-by-step explanation:
17.00 + 88.40 = 105.40
105.40 + 47.60 = 153.00
70% - 20% = 50%
$153.00 divided by 50% = $76.50
The <em><u>correct answer</u></em> is:
x=6/7.
Explanation:
First we find the general form by solving for x:
a-bx = cx+d
Subtract a from each side:
a-bx-a = cx+d-a
-bx = cx+d-a
Subtract cx from each side:
-bx-cx = cx+d-a
-bx-cx = d-a
We can divide both sides by -1:
(-bx-cx)/-1 = (d-a)/-1
bx+cx = -d+a
bx+cx = a-d
Factor out an x on the left:
x(b+c) = a-d
Divide both sides by (b+c):
(x(b+c))/(b+c) = (a-d)/(b+c)
x = (a-d)/(b+c)
In this equation, a = 5, b = 6, c = 8 and d = 17:
x = (5-17)/(6+8) = -12/14
This simplifies to -6/7.
Answer:
Explained below.
Step-by-step explanation:
Denote the variable as follows:
M = male student
F = female student
Y = ate breakfast
N = did not ate breakfast
(a)
Compute the probability that a randomly selected student ate breakfast as follows:

(b)
Compute the probability that a randomly selected student is female and ate breakfast as follows:

(c)
Compute the probability a randomly selected student is male, given that the student ate breakfast as follows:

(d)
Compute the probability that a randomly selected student ate breakfast, given that the student is male as follows:

(e)
Compute probability of the student selected "is male" or "did not eat breakfast" as follows:

(f)
Compute the probability of "is male and did not eat breakfast as follows:

Find the mode, median, mean, and range of 3, 7, 2, 4, 7, 5, 7, 1, 8, 8
leva [86]
Mode-7
Median-6
Mean-5.2
Range-7