Answer:
It is no real solutions
Step-by-step explanation:
Answer: The answer is x = 6 units.
Step-by-step explanation: Please refer to the attached diagram
The diagram in the question shows two triangles placed on each other and for convenience sake has been labelled ABDCE. Triangle ABC is a right angled triangle, and so is triangle ADE. From the marks on the lines, we can infer that line AD is equal in measurement to line DB. Also line AE is equal in measurement to line EC.
Therefore we can see the similarity in both triangles, if AD and AE equals DB and EC, then it follows that DE equals BC.
Hence if AD = DB and
AE = EC, and
DE = BC
Then, x - 3 = ½x
(½x can also be expressed as x/2)
x - 3 = x/2
By cross multiplication we now have
2(x - 3) = x
2x - 6 = x
By collecting like terms we now have
2x - x = 6
x = 6
Answer:
The domain of f is {x : x ∈ R, -7 ≤ x ≤ 7} ⇒ [-7, 7]
Step-by-step explanation:
<em>The domain of a function is </em><em>all the values of x</em><em> make the function defined</em>
In the given graph
∵ The graph drawn from x = -7 to x = 7 and from y = -6 to y = 4
→ That means the values of x started from -7 and ended at x = 7
∵ The coordinates of the starting point of the graph of f are (-7, -5)
∵ The coordinates of the ending point of the graph of f are (7, 3)
∴ -7 ≤ x ≤ 7
∵ Values of x are the domain of the function
∴ The domain of the function is -7 ≤ x ≤ 7
∴ The domain of f = {x : x ∈ R, -7 ≤ x ≤ 7} ⇒ [-7, 7]
<u>Answer:</u>
<u>1. A. You allow the passenger to board his flight when the passenger has a weapon.</u>
<u>2. B. You select the passenger for further inspection when the passenger has no weapon.</u>
<u>Explanation:</u>
1. Remember, a Type I error in simple words means that the assumption "the passenger has a weapon" (null hypothesis) is <em>actually true,</em> but the airport security screener <em>incorrectly concluded it is false. </em>In other words, he assumed the passenger had no weapon and allowed the passenger to board his flight <u>when he actually did have one.</u>
<em>2. While, </em><em>a </em><em>Type II error </em><em>means that </em>the assumption "the passenger has a weapon" (null hypothesis) is <em>actually false, </em>but the airport security screener <em>incorrectly concluded it is true. </em>In other words, he assumed the passenger had a weapon and selected the passenger for further inspection <u>when he actually didn't have one.</u>
Answer:
Then it would be the other way around 19 ≥ k + 6
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