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2 years ago

The image of parallelogram PQRS after a reflection across Line W Y is parallelogram P'Q'R'S'.

Mathematics

2 answers:

GenaCL600 [577]2 years ago

5 0

Answer:

Step-by-step explanation:

Let line WY be the line of reflection

RR has the midpoint at Z.

In other words, the line: $RZ$ = $\frac{1}{2}RR$

SS is another line

It has a midpoint at X. In other words, line SX = $\frac{1}{2} SS$

If SS = 12, then the line SX = $\frac{1}{2} (12)\\ = 6$

Because the shape is a parallelogram, it means that RZ = SX = 6

Luden [163]2 years ago

3 0

Answer:

the answer is 6

Step-by-step explanation:

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Write an equation of the line given.

frozen [14]

Answer:

y = -3/4x + 1

Step-by-step explanation:

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3 years ago

The length of a rectangle is 5.2cm and its breadth is 3.4cm. What is the area of the rectangle?

Rainbow [258]

Answer:

$\huge{ \boxed{ \sf{17.68 \: {cm}^{2} }}}$

Step-by-step explanation:

$\underline{ \text{Given}} :$

$\longrightarrow \sf{ \: Length \: of \: a \: rectangle \: = \: 5.2 \: cm}$

$\longrightarrow{ \sf{Breadth \: of \: \: rectangle \: = \: 3.4 \: cm}}$

$\underline{ \text{To \: find} } : \sf{Area \: of \: a \: rectangle}$

$\boxed{ \sf{Area \: of \: a \: rectangle \: = \: Length \: \times \: Breadth}}$

$\mapsto{ \sf{Area \: = \: 5.2 \: cm \: \times \: 3.4 \: cm}}$

$\mapsto{ \sf{Area \: = \: 17.68 \: {cm}^{2} }}$

Hope I helped!

Best regards! :D

~ $\text{TheAnimeGirl}$

5 0

2 years ago

Is my answer choice wrong or right?

Tasya [4]

Answer:

It is correct

Step-by-step explanation:

Gr8 job

6 0

2 years ago

Please help me this is my last question!!!no scammers plz i got scammed 5 times now

MAVERICK [17]

Answer:

A) 5600 ft

B) 5600 ft

C0 More than a mile

Step-by-step explanation:

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4 0

2 years ago

If (ax+2)(bx+7)=15x2+cx+14 for all values of x, and a+b=8, what are the 2 possible values fo c

dolphi86 [110]

Given:

$(ax+2)(bx+7)=15x^2+cx+14$

And

$a+b=8$

Required:

To find the two possible values of c.

Explanation:

Consider

$\begin{gathered} (ax+2)(bx+7)=15x^2+cx+14 \\ abx^2+7ax+2bx+14=15x^2+cx+14 \end{gathered}$

$\begin{gathered} ab=15-----(1) \\ 7a+2b=c \end{gathered}$

And also given

$a+b=8---(2)$

Now from (1) and (2), we get

$\begin{gathered} a+\frac{15}{a}=8 \\ \\ a^2+15=8a \\ \\ a^2-8a+15=0 \end{gathered}$ $a=3,5$

Now put a in (1) we get

$\begin{gathered} (3)b=15 \\ b=\frac{15}{3} \\ b=5 \\ OR \\ b=\frac{15}{5} \\ b=3 \end{gathered}$

We can interpret that either of a or b are equal to 3 or 5.

When a=3 and b=5, we have

$\begin{gathered} c=7(3)+2(5) \\ =21+10 \\ =31 \end{gathered}$

When a=5 and b=3, we have

$\begin{gathered} c=7(5)+2(3) \\ =35+6 \\ =41 \end{gathered}$

Final Answer:

The option D is correct.

31 and 41

8 0

9 months ago