Something funny is that the x value of the vertex lies directl in the middle of the x intercepts
so
we see the x intercepts or 0's at x=8 and 2
the average is x=5
so find f(5) to find the y value of the vertex
f(5)=(5-8)(5-2)
f(5)=(-3)(3)
f(5)=-9
vertex is at (5,-9)
the actual way the teacher wants is to expand then compltete the square to get into the form f(x)=a(x-h)^2+k where the vertex is (h,k)
but whatever
verrtex is at (5,-9)
The answer would be Associative Property.
Hope this helps you =)
Answer: 1=1 question 2 = 1 again 5-6 is the next and 4 3-10 5-6 next answer2-7 3-8 5-4 -22--9 2-29 are all the answers
Step-by-step explanation:
For the one on the left they are corresponding and on the right they are vertical
Answer:
Step-by-step explanation:
What i would do is multiply both sides by 2z + 1
so you get z-6=20z+10
-19z=16
z=-16/19
