Answer:
21.8
Step-by-step explanation:
Answer:
1. 3 packs of daffodils and 4 packs of tulips
2. then you would have 24 of each
3. $2.29
4. $37.54
5. $34.61
6.$2.93 was saved
7. 3 tulips
8. 12 daffodils
9. 9 tulips
10. 12 daffodils and 15 tulips
theres 2 left. ill let someone else do it
Step-by-step explanation:
3. 4.50*4=18 5.75*3=17.25
18+17.25 -> 35.25*.065=2.29 rounded
4. 35.25+2.29=37.54
5. 35.25-2.75->32.50*.065=2.11 2.11+32.50=34.61
6. 37.54-34.61=2.93
7. 6:8 -> 3:4 ratio -> 3:4
8. 8+4=12
9. 6+3=9
10. 24-12=12 24-9=15
Answer:
Yes
Step-by-step explanation:
X2+10x+25=0
So let's solve
10=5,5
25=5,5
So let's continue
X2+5x+5x+25
Let's factorise
X(x+5)+5(x+5)=0
(X+5)(x+5)=0
So
X+5=0
Substrate 5 from both sides
X=-5(twice)
So the answer is yes
Well this is simple a calculator type problem...but if you are curious as the the algorithm used by simple calculators and such...
They use a Newtonian approximation until it surpasses the precision level of the calculator or computer program..
A newtonian approximation is an interative process that gets closer and closer to the actual answer to any mathematical problem...it is of the form:
x-(f(x)/(df/dx))
In a square root problem you wish to know:
x=√n where x is the root and n is the number
x^2=n
x^2-n=0
So f(x)=x^2-n and df/dx=2x so using the definition of the newton approximation you have:
x-((x^2-n)/(2x)) which simplifies further to:
(2x^2-x^2+n)/(2x)
(x^2+n)/(2x), where you can choose any starting value of x that you desire (though convergence to an exact (if possible) solution will be swifter the closer xi is to the actual value x)
In this case the number, n=95.54, so a decent starting value for x would be 10.
Using this initial x in (x^2+95.54)/(2x) will result in the following iterative sequence of x.
10, 9.777, 9.774457, 9.7744565, 9.7744565066299210578124802523397
The calculator result for my calc is: 9.7744565066299210578124802523381
So you see how accurate the newton method is in just a few iterations. :P
Answer:
2 hours and 7 minutes
Step-by-step explanation:
