All categories

2 years ago

what will be the new coordinate of vertex b if the triangle is dilated with a center at the origin by a scale factor of 1/3

Mathematics

2 answers:

Citrus2011 [14]2 years ago

6 0

Answer:

6,3

Step-by-step explanation:

ser-zykov [4K]2 years ago

4 0

Answer:

6 , 3

Step-by-step explanation:

your welcome

You might be interested in

X/3/4 = 100 what does x equal

Crank

Answer:

x=1200

Step-by-step explanation:

x/3/4=100

Step 1: Multiply both sides by 4.

x/3/4=100

(x/3/4)*(4)=(100)*(4)

x/3=400

Step 2: Multiply both sides by 3.

3*(3/x)=(3)*(400)

x=1200

4 0

2 years ago

ILL MARK YOU BRAINLEST IF YOU AWNSER PLEASE!! look at the photo and what is the measure of BMC?help me please!!

Lesechka [4]

2x + (x+9) = 90
3x + 9= 90
3x= 81
x= 27
Now plug in 27 to (x+9)
27+9= 36
Final Answer = 36

6 0

2 years ago

Solve by the addition method

Sladkaya [172]

Answer is no solution I believe

7 0

3 years ago

In the picture PLEASE HELP

Debora [2.8K]

I believe it's not a function because the input (x) 4 has two outputs(y), 2 and 8.

5 0

2 years ago

Help evaluating the indefinite integral

Dafna11 [192]

Answer:

$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }$

General Formulas and Concepts:
Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]:
$\displaystyle (cu)' = cu'$

Derivative Property [Addition/Subtraction]:
$\displaystyle (u + v)' = u' + v'$
Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Reverse Power Rule]:
$\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]:
$\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Methods: U-Substitution and U-Solve

Step-by-step explanation:

Step 1: Define

Identify given.

$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution/u-solve.

Set u:
$\displaystyle u = 4 - x^2$
[u] Differentiate [Derivative Rules and Properties]:
$\displaystyle du = -2x \ dx$
[du] Rewrite [U-Solve]:
$\displaystyle dx = \frac{-1}{2x} \ du$

Step 3: Integrate Pt. 2

[Integral] Apply U-Solve:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-x}{2x\sqrt{u}}} \, du$
[Integrand] Simplify:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-1}{2\sqrt{u}}} \, du$
[Integral] Rewrite [Integration Property - Multiplied Constant]:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \frac{-1}{2} \int {\frac{1}{\sqrt{u}}} \, du$
[Integral] Apply Integration Rule [Reverse Power Rule]:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = -\sqrt{u} + C$
[u] Back-substitute:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }$

∴ we have used u-solve (u-substitution) to find the indefinite integral.

---

Learn more about integration: brainly.com/question/27746495

Learn more about Calculus: brainly.com/question/27746485

---

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

5 0

1 year ago