Anyone have the answer to this ?

Mathematics

1 answer:

Hoochie [10]2 years ago

5 0

<h3>Solution:</h3>

${x}^{2} + 8x + 12 = 0 \\ = > {x}^{2} + 6x + 2x + 12 = 0 \\ = > x(x + 6) + 2(x + 6) = 0 \\ = > (x + 2)(x + 6) = 0 \\ = > x = 2 \: \: or \: \: x = 6$

<h3>Answer:</h3>

x = 2, x = 6

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