Question

Anyone have the answer to this ?

Answer 1

Solution:

${x}^{2} + 8x + 12 = 0 \\ = > {x}^{2} + 6x + 2x + 12 = 0 \\ = > x(x + 6) + 2(x + 6) = 0 \\ = > (x + 2)(x + 6) = 0 \\ = > x = 2 \: \: or \: \: x = 6$

Answer:

x = 2, x = 6