Answer:
I believe the answer is p over 5, it won't let me type it out but it put the p on top of the 5
If you're solving for x, you'd move all the terms containing x to the left side of the equation:
d^2y/dx^2+4y/x-12y-cos^2(x)+sin^2(x)=0
If you're solving for y, you'd simplify both sides of the equation, then isolating the variable:
y=xcos(2x)
Answer:
14, 15, 16
Step-by-step explanation:
Let integers equal:
x, x + 1, x + 2
2x = 12 + (x + 2)
2x = 12 + x + 2
2x = 14 + x
2x - x = 14
x = 14
x = 14
x + 1 = 14 + 1 = 15
x + 2 = 14 + 2 = 16
Answer:

Step-by-step explanation:

Note that
![x^{3/4 } = \sqrt[4]{x^3}](https://tex.z-dn.net/?f=x%5E%7B3%2F4%20%7D%20%3D%20%5Csqrt%5B4%5D%7Bx%5E3%7D)
![y^{3/8 } = \sqrt[8]{y^3}](https://tex.z-dn.net/?f=y%5E%7B3%2F8%20%7D%20%3D%20%5Csqrt%5B8%5D%7By%5E3%7D)
So,
![\sqrt[4]{x^3} = \sqrt[8]{y^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E3%7D%20%3D%20%20%5Csqrt%5B8%5D%7By%5E3%7D)
![( \sqrt[4]{x^3} ) ^8= ( \sqrt[8]{y^3} )^8](https://tex.z-dn.net/?f=%28%20%5Csqrt%5B4%5D%7Bx%5E3%7D%20%29%20%5E8%3D%20%20%28%20%5Csqrt%5B8%5D%7By%5E3%7D%20%29%5E8)
![( \sqrt[4]{x^3} ) ^8= y^3](https://tex.z-dn.net/?f=%28%20%5Csqrt%5B4%5D%7Bx%5E3%7D%20%29%20%5E8%3D%20%20y%5E3)
Once
![( \sqrt[4]{x^3} )^8 = (( \sqrt[4]{x^3} )^4)^2= (x^3)^2 = x^6](https://tex.z-dn.net/?f=%28%20%5Csqrt%5B4%5D%7Bx%5E3%7D%20%29%5E8%20%3D%20%28%28%20%5Csqrt%5B4%5D%7Bx%5E3%7D%20%29%5E4%29%5E2%3D%20%28x%5E3%29%5E2%20%3D%20x%5E6)

![x = \sqrt[6]{y^3}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Csqrt%5B6%5D%7By%5E3%7D)



Y = -23x + b
1 = -23(5) + b
1 = -115 + b, b = 116
Y = -23x + 116
I choose the slope intercept form since it was easy to calculate. The slope was given, you just need to plot in the points to find the y- intercept.