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3 years ago

Is there a series of rigid transformations that could map A

Mathematics

2 answers:

topjm [15]3 years ago

7 0

Answer:

your answer is C. Yes, Triangle KLP can be reflected across the line containing KP and then translated so that P is mapped to M on edg2020

MaRussiya [10]3 years ago

3 0

Answer:

Yes, A KLP can be reflected across the line containing KP and then translated so that Pis mapped to M.

Step-by-step explanation:

The figure shows two congruent by HA theorem (they have congruent hypotenuses and a pair of congruent angles adjacent to the hypotenuses) triangles KLP and QNM.

A rigid transformation is a transformation which preserves lengths. Reflection, rotation and translation are rigit transformations.

If you reflect triangle KLP across the leg KP and translate it up so that point P coincides with point M , then the image of triangle KLP after these transformations will be triangle QNM.

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Travka [436]

It’s 1.60 because you divide 8.2 from $13.12 and that equals $1.60

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3 years ago

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Law Incorporation [45]

Answer:

Multiply:

$(x+y)by (x+y)$

$: \implies(x + y)(x + y)$

$: \implies \: x(x + y) + y(x + y)$

$: \implies {x}^{2} + xy + xy + {y}^{2}$

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Multiply:

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$: \implies( {a}^{2} + {b}^{2} ) \times (a + b)$

$: \implies \: {a}^{2} (a + b) - {b}^{2} (a + b)$

$: \implies \: {a}^{3} + {a}^{2} b - {ab}^{2} - {b}^{3}$

Multiply:

$(a+5) by (a^2-2a-3)$

$: \implies{(a + 5) \times ( {a}^{2} - 2a - 3) }$

$: \implies \: a({a}^{2} - 2a - 3) + 5( {a}^{2} - 2a - 3)$

$: \implies(a \times {a}^{2} - a \times 2a - a \times 3) + (5 \times {a}^{2} - 5 \times 2a - 5 \times 3)$

$: \implies{a}^{3} - {2a}^{2} - 3a + 5 {a}^{2} - 10a - 15$

$: \implies{ {a}^{3} + {3a}^{2} - 13a - 15}$

Multiply:

$(a^2-ab+b^3) by (a+b)$

$: \implies{(a + b) \times ( {a}^{2} - ab + {b}^{3} )}$

$: \implies \: a( {a}^{2} - ab + {b}^{3}) + b( {a}^{2} - ab + {b}^{3} )$

$: \implies {a}^{3} - {a}^{2} b + a {b}^{3} + {a^2b} - {ab}^{2} + {b}^{4}$

$: \implies{ {a}^{3}+ab^3 - ab^2+ {b}^{4} }$

Step-by-step explanation:

$\blue{ \frak{Seolle_{aph.rodite}}}$

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2 years ago

Choose the point-slope form of the equation below that represents the line that passes through the points (-6, 4) and (2, 0).

Pavlova-9 [17]

Point slope form
y-y1=m(x-x1)
slope=m
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slope=(y2-y1)/(x2-x1)
given
(-6,4) and (2,0)
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a point is (-6,4)
x1=-6
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not listed

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3 years ago

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bixtya [17]

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Fantom [35]

Answer:

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Step-by-step explanation:

1 : 2/3

= 3/2 : 1

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3 years ago

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