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3 years ago

Does anyone know the answer to this and how to solve it? I’m completely lost-

Mathematics

1 answer:

vovangra [49]3 years ago

7 0

Answer:

314

Step-by-step explanation:

Does the line cuts through the diameter of the circle?

If so just apply π * 10^2 = 314.15 radius is just 20/2 = 10

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I need help with question 43. 44. 45.

mixas84 [53]

Answer:

44 is also NOT divisible by 3

45 is divisible by 11. Here is the math: 4 - 5 = -1

hope this helps i am not to sure about 43

Step-by-step explanation:

5 0

3 years ago

Ully is having a party and wants to fill his swimming pool. if he only uses his hose it takes 2 hours more than if he only uses

nikklg [1K]

I believe it takes 3 hours

5 0

4 years ago

A bag contains 30 cookies: 9 vanilla, 9 chocolate, and 12 oatmeal. What is the probability that a chocolate is randomly selected

telo118 [61]

There is 9 chocolate cookies, so the probability of choosing chocolate is $\frac{9}{30}$ . We then simplify to get $\frac{3}{10}$ , or 0.3.

3 0

3 years ago

Given 1+cosx\sinx+sinx\1+cosx=4, find a numerical value of one trigonometric function of x.

Len [333]

Answer:

Option d. $sin(x)=\frac{1}{2}$

Step-by-step explanation:

The complete question is

Given (1+cosx)/(sinx) + (sinx)/(1+cosx) =4, find a numerical value of one trigonometric function of x.

a. tanx=2

b. sinx=2

c. tanx=1/2

d. sinx=1/2

we have

$\frac{1+cos(x)}{sin(x)}+\frac{sin(x)}{1+cos(x)}=4$

Find the common denominator and adds the fractions

$\frac{(1+cos(x))^2+sin^2(x)}{(1+cos(x))sin(x)}=4$

Expanded the numerator

$\frac{(1+2cos(x)+cos^2(x)+sin^2(x)}{(1+cos(x))sin(x)}=4$

Remember that

$sin^2(x)+cos^2(x)=1$ ----> trigonometric identity

substitute

$\frac{1+2cos(x)+1}{(1+cos(x))sin(x)}=4$

$\frac{2+2cos(x)}{(1+cos(x))sin(x)}=4$

Factor 2 in the numerator

$\frac{2(1+cos(x))}{(1+cos(x))sin(x)}=4$

Simplify

$\frac{2}{sin(x)}=4$

$sin(x)=\frac{1}{2}$

7 0

3 years ago

Use the drop-down menus to complete the statements about factoring 14x2 + 6x – 7x – 3 by grouping. The GCF of the group (14x2 –

Yuliya22 [10]

14 x² + 6 x - 7 x - 3 =
= ( 14 x² - 7 x ) + ( 6 x - 3 ) =
= 7 x ( 2 x - 1 ) + 3 ( 2 x - 1 ) =
= ( 2 x - 1 ) ( 7 x + 3 )
Answer:
1. GCF of the group ( 6 x - 3 ) is 3.
2. The common binomial factor is 2 x - 1.
3. The factored expression is: ( 2 x - 1 ) ( 7 x + 3 ).

8 0

3 years ago

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