Answer:
if 12 moles are produced then it came 24 moles of Al(OH)3
Explanation:
Answer:
first at start Aarau so I just way we Z
The correct answer would be the second option. It would would need 2 moles of electrons to reduce one mole of bromine gas into two moles of the bromide ions. This is a reduction reaction. It would be written as:
Br2 = 2Br- + 2e-
Answer:
V₂ = 155.2 mL
Explanation:
Given data:
Initial volume =175.6 mL
Initial pressure =0.9648 atm
Initial temperature = 298.1 K
Final temperature = 273 K
Final volume =?
Final pressure = 1 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁T₂ /T₁P₂
V₂ = 0.9648 atm × 175.6 mL × 273 k / 298.1 K× 1 atm
V₂ = 46251.4 atm. k. mL/ 298.1 K× 1 atm
V₂ = 155.2 mL
